A. DNA polymorphism plays important role in evolution and speciation.
B. 99.9% nucleotides bases are exactly same in all people
C. Chromosome 1 has the fewest genes (23) and Y-chromosomes has most genes (2968)
D. BAC and YAC have been used in Human Genome Project.
1. All correct
2. All incorrect
3. A, B, D are correct
4. B, C, D are correct
Go through the following diagram of Nucleosome (structural unit of chromatin). Identify its componential parts indicated by A, B and C:
|
A |
B |
C |
1. |
RNA |
Non histone |
Histone |
2. |
DNA |
H1 histone |
Histone Octamer |
3. |
RNA |
Histone Octamer |
H1 histone |
4. |
DNA |
Non histone |
Histone |
Following is the schematic structure of transcription unit having some important components indicated by A, B, C, D and E. In which of four option the components are identified correctly:
|
A |
B |
C |
D |
E |
1. |
Terminator |
Transcription start site |
Promoter |
Template strand |
Coding strand |
2. |
Promoter |
Transcription start site |
Terminator |
Coding strand |
Template strand |
3. |
Promoter |
Transcription start site |
Terminator |
Template strand |
Coding strand |
4. |
Terminator |
Transcription start site |
Promoter |
Coding strand |
Template strand |
The fact that the genetic code is almost universal in living organisms is considered to be evidence that all organisms:
1. Are evolutionarily related
2. Are genetically identical
3. Have the same sequence of anticodons
4. None of the above
In the following diagram of the lac operon, an operon for inducible enzymes, identify components and enzymes:
|
X |
Y |
E1 |
E2 |
E3 |
1. |
Repressor protein |
Inducer (lactose) |
â-Galactosidase |
Permease |
Transacetylase |
2. |
Inducer (lactose) |
Repressor protein |
â-Galactosidase |
Permease |
Transacetylase |
3. |
Repressor protein |
Inducer (lactose) |
â-Galactosidase |
Transacetylase |
Permease |
4. |
Repressor protein |
Inducer (lactose) |
Permease |
Transacetylase |
â-Galactosidase |
Alfred Hershey and Martha Chase made a big contribution in proving DNA role as the hereditary molecule. The experiment is shown in the diagram. A and C are the presence or absence of radioactivity detected in cells B and D are the presence or absence of radioactivity detected in supernatants cells. Identify A, B, C and D:
1. A - No Radioactivity (35S) detected in cells; B - Radioactivity (32P) detected in supernatant; C - Radioactivity (35S) detected in cells; D - No Radioactivity in supernatant
2. A- Radioactivity (35S) detected in cells; B - No Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant
3. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant
4. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - No Radioactivity (32P) detected in cells; D - Radioactivity in supernatant
If the DNA of this virus was labeled with 32P and the protein of the virus was labeled with 35S, which molecule(s) would be present inside the cells?
1. 35S and 32P
2. 35S only
3. 32P only
4. Neither molecule would be present inside the cell
The prediction of sequence of amino acid is _____A ____ if the sequence of nucleotides mRNA is known. The prediction of sequence of nucleotide in concerned mRNA is ____B____ because the genetic code is _____C_____:
1. A - possible, B - impossible, C - universal
2. A - possible, B - impossible, C - degenerate
3. A - impossible, B - possible, C - universal
4. A - impossible, B - possible, C - degenerate
Choose the correct statements:
I. Binding of mRNA to the ribosome is loose and reversible.
II. The ribosome, which is composed of tRNA and proteins, consists of a small and large subunit.
III. Each of the 20 amino acids has a minimum of one specific tRNA molecule.
IV. tRNAMET binds to the first codon (AUG) - this is called the START codon.
V. The second tRNA binds to the second codon so that their attached monosaccharides are next to each other
VI. The newly formed polypeptide may undergo post-transcriptional modification.
1. I, III and IV
2. II, IV, VI
3. II, V and VI
4. I, V, VI
If a length of DNA has 45,000 base pairs, how many complete turns will the DNA molecule take?
1. 45000
2. 450
3. 4500
4. 45