Among the following the correct order of acidity is-
1. HClO < HClO2< HClO3< HClO4
2. HClO2< HClO < HClO3< HClO4
3. HClO4< HClO2< HClO < HClO3
4. HClO3< HClO4< HClO2< HClO
What is the alteration in the oxidation state of carbon in the given reaction?
\(\mathrm{{CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}}\)
1. | 0 to +4 | 2. | –4 to +4 |
3. | 0 to –4 | 4. | +4 to +4 |
The standard electrode potential (E°) values of Al3+/ Al, Ag+ / Ag, K+ / K, and Cr3+ / Cr are –1.66 V, 0.80 V, –2.93 V, & –0.79 V respectively. The correct decreasing order of the reducing power of the metal is:
1. | Ag > Cr > Al > K | 2. | K > Al > Cr > Ag |
3. | K > Al > Ag > Cr | 4. | Al > K > Ag > Cr |
The oxidation state of Cr in is -
1. | –6 | 2. | +12 |
3. | +6 | 4. | +4 |
The incorrect oxidation number of the underlined atom in the following species is:
1. | Cu2O is -1 | 2. | Cl\(O_{3}^{-}\) is +5 |
3. | K2Cr2O7 is +6 | 4. | HAuCl4 is +3 |
From the following, identify the reaction having the top position in the EMF series (standard reduction potential) according to their electrode potential at 298 K.
1. Mg2++ 2e–Mg(s)
2. Fe2+ + 2e– Fe(s)
3. Au3++ 3e–Au(s)
4. K++ le –K(s)
Standard reduction potentials of the half-reactions are given below:
The strongest oxidizing and reducing agents, respectively, are:
1. and
2. and
3. and
4. and
A solution contains Fe2+, Fe3+ and I– ions. This solution was treated with iodine at 35°C. E° for Fe3+/Fe2+ is +0.77 V and E° for I2/2I– = 0.536 V.
The favourable redox reaction is:
1. Fe2+ will be oxidized to Fe3+.
2. I2 will be reduced to I–.
3. There will be no redox reaction.
4. I– will be oxidized to I2.
a | b | c | d | e | f | |
1. | 2 | 4 | 6 | 8 | 4 | 2 |
2. | 1 | 4 | 10 | 3 | 1 | 4 |
3. | 4 | 1 | 10 | 1 | 3 | 4 |
4. | 10 | 4 | 1 | 3 | 4 | 2 |
Best description of the behavior of bromine in the reaction given below is:
1. Both oxidized and reduced
2. Oxidized only
3. Reduced only
4. Proton acceptor only