Q. No.The correct statement regarding the bond angle of H2O and H2S is:
1. Both have the same bond angle.
2. Bond angle of H2O is larger than that of H2S
3. Bond angle of H2O is smaller than that of H2S
4. None of the above.
PCl5 reacts with finely divided silver on heating and a white silver salt is obtained, which dissolves on adding excess aqueous NH3 solution gives "A". Compond A is :
1. \([Ag(NH_{3})_{2}]Cl\)
2. \([Ag(NH_{3})_{2}]Cl_{2}\)
3. \([Ag(NH_{3})_{4}]Cl_{3}\)
4. \([Ag(NH_{3})_{}]Cl_{2}\)
Phosphorus forms a number of oxoacids. Out of these oxoacids, phosphinic acid has strong reducing property. its structure and reaction is
1. 
2.
2Ag + H3PO3 + 2HNO3
3.
4.
An amorphous solid“A” burns in the air to form a gas “B” which turns lime water milky. The gas is also produced as a by-product during the roasting of sulphide ore. This gas decolourises acidified aqueous KMnO4 solution and reduces Fe3+ to Fe2+. The solid "A" and the gas "B" are:
1. 'A' = S8: ‘B' = SO2
2. 'A' = S8: ‘B' = SO3
3. 'A' = S10: ‘B' = SO2
4. Not predictable
On heating lead (II) nitrate gives a brown gas “A” The gas “A” on cooling changes to colourless solid “B”. Solid “B” on heating with NO changes to a blue solid ‘C’.
Identify ‘A’, ‘B’ and ‘C and also write reactions involved and draw the structures of ‘B’ and ‘C’.
1. , and
2. , and
3. , and
4. None of above
On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 moles of hydrogen (H2) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Compounds (A) and (D) are :
1. A = N2 ; D = HNO3
2. A = NH4NO2 ; D = HNO3
3. A = NH4NO2 ; D = NH3
4. A = NH4NO2 ; D = HNO2
| Assertion (A): | R3P = O exists but R3N = O does not (R = alkyl group). |
| Reason (R): | Nitrogen doesn't have d orbitals. |
| 1. | (A) is true and (R) is the correct explanation of (A). |
| 2. | (A) is true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false |
| Assertion (A) | Nitrogen exists as a diatomic molecule and phosphorus as P4. |
| Reason (R) | Phosphorus is smaller in size, so it can form P4. |
| 1. | (A) is true and (R) is the correct explanation of (A). |
| 2. | (A) is true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false |
The disproportionation reaction of is as follows:
X and Y in the above reaction are:
1. H3PO2, HPO2
2. H3PO4, PH3
3. H2PO6, PO3
4. None of the above.
| Assertion (A): | Phosphorous (V) has a tendency to only gain electrons as it is in its highest oxidation state |
| Reason (R): | PCl5 can act as an oxidizing as well as a reducing agent. |
| 1. | (A) is true and (R) is the correct explanation of (A). |
| 2. | (A) is true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false |
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