0.3780 grams of an organic chloro compound gave 0.5740 grams of silver chloride in Carius estimation. % of chlorine present in the compound is -
1. | 25% | 2. | 37.59% |
3. | 42% | 4. | 05.70 % |
In the Carius method, 0.468 grams of an organic sulphur compound gives 0.668 grams of barium sulphate. The percentage of sulphur in the given compound is -
1. | 19.59% | 2. | 25.40% |
3. | 09.24% | 4. | 27.59% |
The most stable carbocation among the following is-
1. \(({CH_3})_3C\overset{+}{C}H_2\)
2. \(({CH_3})_3\overset{+}{C}\)
3. \({CH_3}CH_2\overset{+}{C}H_2\)
4. \(({CH_3})\overset{+}{C}HCH_2CH_3\)
is more stable than because :
1. | NO2 shows +I effect |
2. | NO2 shows -I effect |
3. | NO2 decreases the positive charge on the compound |
4. | Ethyl group increases positive charge on the compound |
Alkyl groups act as electron donors when attached to a π system due to:
1. | Inductive effect | 2. | Mesomeric effect |
3. | Resonance | 4. | Hyperconjugation |
An electrophile among the following is :
1. | \(\mathrm{OH}^-\) | 2. | \(\mathrm{NC}^-\) |
3. | \(R_3C^-\) | 4. | Carbonyl group |
Which of the following reactions is an elimination reaction?
1. | CH3CH2Br + HS- → CH3CH2SH + Br- |
2. | ( CH3)2C=CH2 + HCl → (CH3)2ClC-CH3 |
3. | CH3CH2Br+HO- → CH2=CH2 + Br-+H2O |
4. | (CH3)3C-CH2OH + HBr → (CH3)2CBrCH2CH3 + H2O |
Free radical formation will take place in :
1. | |
2. | |
3. | |
4. |
The effect that can explain the given order of acidity of the carboxylic acids is-
Cl3CCOOH > Cl2CHCOOH > ClCH2COOH
1. +I effect
2. -I effect
3. +E effect
4. -E effect