Q. No.In nitration of benzene using a mixture of conc. H2SO4 and conc. HNO3, the species that initiates the reaction is :
1. NO2
2. NO+
3. NO2+
4. NO2-
2. NO+
3. NO2+
4. NO2-
Match the compounds given in Column I with the items given in Column II.
| Column I | Column II | ||
| A. | Benzene sulphonyl chloride | I. | Zwitter ion |
| B. | Sulphanilic acid | II. | Hinsberg reagent |
| C. | Alkyl diazonium salts | III. | Dyes |
| D. | Aryl diazonium salts | IV. | Conversion to alcohols |
Codes:
| A | B | C | D | |
| 1. | II | I | IV | III |
| 2. | III | I | IV | II |
| 3. | I | IV | III | II |
| 4. | IV | III | II | I |
Select the correct option based on statements below:
| Assertion (A): | N-Ethylbenzene sulphonamide is soluble in alkali. |
| Reason (R): | The hydrogen attached to nitrogen in sulphonamide is strongly acidic. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Select the correct option based on statements below:
| Assertion (A): | Only a small amount of HCI is required in the reduction of nitro compounds with iron scrap and HCI in the presence of steam. |
| Reason (R): | FeCl2 formed gets hydrolyzed to release HCI during the reaction. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
The A and B in the above reactions are -
| 1. | Alcohol, Diazonium salt | 2. | Aldehyde, Diazonium salt |
| 3. | Diazonium salt, Alcohol | 4. | Diazonium salt, Aldehyde |
Amines are less acidic than alcohols of comparable molecular masses because :
1. N is more electronegative than O.
2. O is more electronegative than N.
3. N can accomodate negative charge easily than O
4. Amides are more stable than alcohols
1. \(\mathrm{SOCl}_2 \)
2. \(\mathrm{NaNH}_2 \)
3. \(\mathrm{PCl}_5 \)
4. \(\mathrm{Sn} / \mathrm{HCl}\)
An aromatic compound ‘A’ on treatment with ammonia and heating forms compound ‘B’ which on heating with Br2 and KOH forms a compound ‘C’ of molecular formula C6H7N. The Substrate 'A' is:
1. Aniline
2. Benzoic acid
3. Benzamide
4. Benzamine
The correct increasing order of basic strength for the following compounds is:
 |
 |
 |
| (I) | (II) | (III) |
1. II < III < I
2. III < I < II
3. III < II < I
4. II < I < III
| 1. | Ethylamine | 2. | Methylamine |
| 3. | Propylamine | 4. | Aniline |
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