The reagent employed in converting nitromethane to methylamine is:
1. \(\mathrm{SOCl}_2 \)
2. \(\mathrm{NaNH}_2 \)
3. \(\mathrm{PCl}_5 \)
4. \(\mathrm{Sn} / \mathrm{HCl}\)

An aromatic compound ‘A’ on treatment with ammonia and heating forms compound ‘B’ which on heating with Br₂ and KOH forms a compound ‘C’ of molecular formula C₆H₇N. The Substrate 'A' is:

1. Aniline

2. Benzoic acid 

3. Benzamide

4. Benzamine

Amines are less acidic than alcohols of comparable molecular masses because :

1. N is more electronegative than O.

2. O is more electronegative than N.

3. N can accomodate negative charge easily than O

4. Amides are more stable than alcohols

$\left(i\right) Aromatic amine + Nitrous acid \to A$
$\left(ii\right) Aliphatic amine + Nitrous acid \to B$

The A and B in the above reactions are -

Select the correct option based on statements below:

Select the correct option based on statements below:

Match the compounds given in Column I with the items given in Column II.

Codes:

In nitration of benzene using a mixture of conc. H₂SO₄ and conc. HNO₃, the species that initiates the reaction is :

1. NO₂
2. NO⁺
3. NO₂⁺
4. NO₂^-

The correct increasing order of basic strength for the following compounds is:

(I)	(II)	(III)

 
1. II < III < I

2. III < I < II

3. III < II < I

4. II < I < III