When NaCl solution is electrolysed using Pt electrodes then pH of solution

1. Increases

2. Decreases

3. Remains same

4. Firstly increases and then decreases

Subtopic:  Relation between Emf, G, Kc & pH |
 62%
From NCERT
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The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
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Electrolysis of hot aqueous solution of NaCl gives NaClO4 as-

NaCl +4H2O           NaClO4 + 4H2

How many faraday are required to obtain 1000 g of sodium perchlorate ?

(1) 66 F

(2) 122.5 F

(3) 15.13 F

(4) 1.86 F

Subtopic:  Faraday’s Law of Electrolysis |
 60%
From NCERT
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A button cell used in watches functions as following

Zn(s) + Ag2O(s) + H2O (l) 2Ag(s) + Zn2+(aq) + 2OH-(aq)

If half cell potentials are

Zn2+aq +2e-  Znx; Eo = -0.76VAg2Os + H2Ol + 2e-  2Ags + 2OH-aq; Eo = 0.34V

The cell potential will be

1. 0.84 V

2. 1.34 V

3. 1.10 V

4. 0.42 V

 

 

Subtopic:  Electrolytic & Electrochemical Cell |
 82%
From NCERT
NEET - 2013
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Limiting molar conductivity of NH4OH (i.e Åm(NH4OH)) is equal to:-

1. Åm (NH4Cl)+Åm(NaCl)-Åm(NaOH) 

2. Åm(NaOH)+Åm(NaCl)-Åm(NH4Cl)

3. Åm(NH4OH)+Åm(NH4Cl)-Åm(HCl)

4. Å(NH4Cl)+Å(NaOH)-Å(NaCl)

Subtopic:   Kohlrausch Law & Cell Constant |
 83%
From NCERT
NEET - 2012
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The efficiency of a fuel cell is given by:

(a) H/G                      (b) G/S
(c) G/H                      (d) S/G

Subtopic:  Hydrogen Economy |
 66%
NEET - 2007
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A hypothetical electrochemical cell is shown below A l A+ (xM)l l B+ (yM) l B
The Emf measured is +0.20 V.The cell reaction is:-
(1) A+ B → A + B+

(2) A+ e→  A ; B+ e→ B

(3) the cell reaction cannot be predicted

(4) A + B→ A+ B

Subtopic:  Nernst Equation |
 72%
From NCERT
NEET - 2006
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Based on the given data, what is the value of the molar conductivity at infinite dilution (Λm) for SrCl₂ in water at 25°C?

( Conc. (mol/lt)    0.25  1
(  Λ m–1 cm2 mol–1)1 260     250

1. 270

2. 260

3. 250

4. 255

Subtopic:  Conductance & Conductivity |
 56%
From NCERT
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During electrolysis of conc. H2SO4, perdisulphuric acid (H2S2O8), and O2 form in equimolar amount. The amount of H2 that will form simultaneously will be : 

1. Thrice that of O2 in moles.

2. Twice that of O2 in moles.

3. Equal to that of O2 in moles.

4. Half of that of O2 in moles.

Subtopic:  Faraday’s Law of Electrolysis |
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What happens to the voltage in a galvanic cell when the salt bridge is removed?

1. The voltage drops to zero.
2. The voltage remains the same.
3. The voltage gradually increases.
4. The voltage rapidly increases.

Subtopic:  Batteries & Salt Bridge |
 78%
From NCERT
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