When 2-Bromopentane reacts with ethanolic KOH, the main product that is formed is:

1.	Cis-2-pentene	2.	Trans-2-pentene
3.	1-pentene	4.	None of the above

Phenylacetylene undergoes a reaction with dilute H₂SO₄ in the presence of HgSO₄ to yield:
 

1.		2.
3.		4.

Compound 'A' on chlorination gives compound 'B'. 'B' reacts with alc. KOH to give gas 'C' which decolorizes Baeyer reagent. Ozonolysis of compound 'C' gives only HCHO compound. Compound 'A' is

The reaction of HBr with propene in the presence of peroxide gives:

1. 3-bromopropane

2. Allyl bromide

3. n-propyl bromide

4. Isopropyl bromide 

Using anhydrous AlCl₃ as a catalyst, one of the following reaction that produces ethylbenzene (PhEt) is:

1. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2+{\mathrm{C}}_6{\mathrm{H}}_6$

2. ${\mathrm{H}}_2\mathrm{C}={\mathrm{CH}}_2+{\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{H}}_3\mathrm{C}-{\mathrm{CH}}_3+{\mathrm{C}}_6{\mathrm{H}}_6$

4. ${\mathrm{H}}_3\mathrm{C}-{\mathrm{CH}}_2\mathrm{OH}+{\mathrm{C}}_6{\mathrm{H}}_6$

The molecular formula of diphenylmethane is C₁₃H₁₂.
The number of structural isomers possible when one of the hydrogens is replaced by a chlorine atom is:

On ozonolysis, the alkene that gives the following product is:

1.
2.	\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CHCH}_2 \mathrm{CH}_3\)
3.	\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CHCH}_3\)
4.

A compound possessing optical isomerism provided it has the molecular formula C₇H₁₆, would be:

The compound  on reaction with NaIO₄ in the presence of KMnO₄ gives:

1. CH₃COCH₃

2. CH₃COCH₃ + CH₃COOH

3. CH₃COCH₃ + CH₃CHO

4. CH₃CHO + CO₂

Among the following, the correct example of a free-radical substitution reaction is:

1.
2.
3.
4.