Q. No.The volume occupied by an atom is greater than the volume of the nucleus by a factor of about:
1. \(10\)
2. \(10^5\)
3. \(10^{10}\)
4. \(10^{15}\)
1. \(10\)
2. \(10^5\)
3. \(10^{10}\)
4. \(10^{15}\)
If the mass of the iron nucleus is \(55.85~\text{u}\) and \(\mathrm{A} = 56\), the nuclear density of the iron is:
| 1. | \(2.27\times10^{17}~\text{kg m}^{-3}\) |
| 2. | \(1.36\times 10^{15}~\text{kg m}^{-3}\) |
| 3. | \(3.09\times10^{17}~\text{kg m}^{-3}\) |
| 4. | \(4.11\times10^{15}~\text{kg m}^{-3}\) |
The energy required in \(\text{MeV/c}^2 \) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given: mass defect for \({ }_8^{16} \mathrm{O}=0.13691~ \text{amu}\))
| 1. | \(127.5\) | 2. | \(120.0\) |
| 3. | \(222.0\) | 4. | \(119.0\) |
A nucleus with mass number \(240\) breaks into fragments each of mass number \(120.\) The binding energy per nucleon of unfragmented nuclei is \(7.6~\text{MeV}\) while that of fragments is \(8.5~\text{MeV}.\) The total gain in the binding energy in the process is:
1. \(804~\text{MeV}\)
2. \(216~\text{MeV}\)
3. \(0.9~\text{MeV}\)
4. \(9.4~\text{MeV}\)
| 1. | \(\beta^{+}, ~\alpha, ~\beta^{-}\) | 2. | \(\beta^{-}, ~\alpha, ~\beta^{+}\) |
| 3. | \(\alpha, ~\beta^{-},~\beta^{+}\) | 4. | \(\alpha, ~\beta^{+},~\beta^{-}\) |
| 1. | \(Z\) protons and \(A-Z\) neutrons |
| 2. | \(Z\) protons and \(A\) neutrons |
| 3. | \(A\) protons and \(Z-A\) neutrons |
| 4. | \(Z\) neutrons and \(A-Z\) protons |
\({}_{92}^{235}\mathrm{U}+ {}_{0}^{1}\mathrm{n}\rightarrow {}_{56}^{144}\mathrm{Ba}+...+3{}_{0}^{1}\mathrm{n}\)
The blank space can be filled by:
| 1. | \({}_{26}^{89}\mathrm{Kr}\) | 2. | \({}_{36}^{89}\mathrm{Kr}\) |
| 3. | \({}_{26}^{90}\mathrm{Sr}\) | 4. | \({}_{38}^{89}\mathrm{Sr}\) |
The binding energy per nucleon in deuterium and helium nuclei are \(1.1\) MeV and \(7.0\) MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:
1. \(2.2\) MeV
2. \(28.0\) MeV
3. \(30.2\) MeV
4. \(23.6\) MeV
What happens to the mass number and the atomic number of an element when it emits \(\gamma\text{-}\)radiation?
| 1. | mass number decreases by four and atomic number decreases by two. |
| 2. | mass number and atomic number remain unchanged. |
| 3. | mass number remains unchanged while the atomic number decreases by one. |
| 4. | mass number increases by four and the atomic number increases by two. |
The mass number of a nucleus is equal to:
| 1. | the number of neutrons in the nucleus. |
| 2. | the number of protons in the nucleus. |
| 3. | the number of nucleons in the nucleus. |
| 4. | none of them. |
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