${\mathrm{H}}_3{\mathrm{CO}}^{-}$ ion is a-

1. carbocation

2. nucleophile

3. electrophile

4. carboanion

${\mathrm{Br}}^{-}$ ion is a -

1. carbocation

2. carboanion 

3. electrophile

4. nucleophile

${\mathrm{H}}_3\mathrm{COH}$ molecule is -

1. carbocation

2. nucleophile

3. electrophile

4. carboanion

The species present below is

$\mathrm{R}-\mathrm{NH}-\mathrm{R}$

1. nucleophile

2. carbocation

3. electrophile

4. carboanion

Chlorine atom can be classified as:

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are - 

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are:
\({ }^1 \mathrm{CH}_3-\mathrm{ }^2{C} \mathrm{H}={}^3{\mathrm{C}} \mathrm{H}_2 \)

$$

The correct hybridization  of carbon atoms are:    

1. C₁= sp , C₂= sp³ , C₂= sp²

2. C₁= sp² , C₂= sp³ , C₂= sp³

3. C₁= sp³ , C₂= sp² , C₂= sp³

4. C₁= sp³ , C₂= sp³ , C₂= sp³

The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{ \; \; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$
 

The correct hybridization states of carbon atoms in C₆H_{6 (cyclic compound)} is/are:

1.  sp² 

2. sp

3. sp³

4.  All of the above