1. | 2. | ||
3. | 4. |
List - I | List - II | ||
(Type of cross) | (Phenotypic ratio) | ||
(A) | Monohybrid cross | (I) | 1:1 |
(B) | Dihybrid cross | (II) | 1:2:1 |
(C) | Incomplete dominance | (III) | 3:1 |
(D) | Test cross | (IV) | 9:3:3:1 |
Options: | (A) | (B) | (C) | (D) |
1. | III | IV | II | I |
2. | II | IV | III | I |
3. | II | III | IV | I |
4. | IV | III | I | II |
1. | Thalassemia | 2. | Sickle cell anemia |
3. | Haemophilia | 4. | Phenylketonuria |
1. | 9 | 2. | 16 |
3. | 4 | 4. | 6 |
A: | There is a change in the gene for beta-globin |
B: | In beta-globin, there is a valine in place of Lysine |
C: | It is an example of point mutation |
D: | In the normal gene, U is replaced by A |
1. | (B), (C) and (D) only | 2. | (B) and (D) only |
3. | (A), (B) and (D) only | 4. | (A) and (C) only |
A: | It is an example of female heterogamety |
B: | Male produces two different types of gametes either with or without X chromosomes. |
C: | Total number of chromosomes (autosomes and sex chromosomes) is same in both males and females. |
D: | All eggs bear an additional X chromosome besides the autosomes. |
1. | (B) and (D) only | 2. | (A), (C) and (D) only |
3. | (A) only | 4. | (A) and (C) only |
Assertion (A): | In Mendelian experiments, phenotype of F1 heterozygote is exactly like the dominant parent in appearance. |
Reason (R): | In a pair of dissimilar factors, one dominates the other while other factor is recessive. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | The original phenotype is due to dominant allele and the recessive phenotype is due to modified allele. |
Reason (R): | The dominant allele produces functional enzyme and the modified alleles generally produce non-functional or no enzyme at all. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |
Assertion (A): | When \(I^A\) and \(I^B \) are present together, they both express their own types of sugars. |
Reason (R): | Alleles \(I^A\) and \(I^B \) show incomplete dominance. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | Both (A) and (R) are false. |