In a typical Wheatstone network, the resistances in cyclic order are A = 10 Ω, B = 5 Ω, C = 4 Ω and D = 4 Ω for the bridge to be balanced 

1. 10 Ω should be connected in parallel with A

2. 10 Ω should be connected in series with A

3. 5 Ω should be connected in series with C

4. 5 Ω should be connected in parallel with B

In the circuit shown in figure, the current drawn from the battery is 4A. If 10 Ω resistor is replaced by 20 Ω resistor, then current drawn from the circuit will be 

1. 1 A

2. 2 A

3. 3 A

4. 4 A

If each of the resistance of the network shown in the figure is R, the equivalent resistance between A and B is 

1. 5 R

2. 3 R

3. R

4. R/2

Thirteen resistances each of resistance R ohm are connected in the circuit as shown in the figure below. The effective resistance between A and B is 

1. 2R Ω

2. $\frac{4R}{3}\Omega$

3. $\frac{2R}{3}\Omega$

4. R Ω

For what value of unknown resistance X, the potential difference between B and D will be zero in the circuit shown in the figure 

1. 4 Ω

2. 6 Ω

3. 2 Ω

4. 5 Ω

An unknown resistance R₁ is connected in series with a resistance of 10 Ω. This combinations is connected to one gap of a metre bridge while a resistance R₂ is connected in the other gap. The balance point is at 50 cm. Now, when the 10 Ω resistance is removed the balance point shifts to 40 cm. The value of R₁ is (in ohm) 

1. 60

2. 40

3. 20

4. 10

A wire has a resistance of 6 Ω. It is cut into two parts and both half values are connected in parallel. The new resistance is :

1. 12 Ω

2. 1.5 Ω

3. 3 Ω

4. 6 Ω

Six equal resistances are connected between points P, Q and R as shown in the figure. Then the net resistance will be maximum between

1. P and Q

2. Q and R

3. P and R

4. Any two points

The total current supplied to the circuit by the battery is:

1. \(1~\text{A}\)
2. \(2~\text{A}\)
3. \(4~\text{A}\)
4. \(6~\text{A}\)