The terminal potential difference of a cell when short-circuited is (E = E.M.F. of the cell)

(1) E

(2) E/2

(3) Zero

(4) E/3

The potential difference in open circuit for a cell is 2.2 volts. When a 4-ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be :

(1) 1 ohm

(2) 0.2 ohm

(3) 2.5 ohm

(4) 0.4 ohm

A cell whose e.m.f. is 2 V and internal resistance is 0.1 Ω, is connected with a resistance of 3.9 Ω. The voltage across the cell terminal will be :

(1) 0.50 V

(2) 1.90 V

(3) 1.95 V

(4) 2.00 V

n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is 

(1) $\frac{nE}{R+nr}$

(2) $\frac{nE}{nR+r}$

(3) $\frac{E}{R+nr}$

(4) $\frac{nE}{R+r}$

A cell of internal resistance r is connected to an external resistance R. The current will be maximum in R, if :

(1) R = r

(2) R < r

(3) R > r

(4) None of these

Two identical cells send the same current in 2 Ω resistance, whether connected in series or in parallel. The internal resistance of the cell should be 

(1) 1 Ω

(2) 2 Ω

(3) $\frac{1}{2}\Omega$

(4) 2.5 Ω

The internal resistances of the two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell :

(1) B will be zero

(2) A will be zero

(3) A and B will be 2V

(4) A will be > 2V and B will be < 2V

The figure shows a network of currents. The magnitude of currents is shown here. The current i will be 

(1) 3 A

(2) 13 A

(3) 23 A

(4) – 3 A

A battery of emf \(E\) and internal resistance \(r\) is connected to a variable resistor \(R\) as shown below. Which one of the following is true​​​​​?

Consider the circuit given here with the following parameters E.M.F. of the cell = 12 V. Internal resistance of the cell = 2 Ω. Resistance R = 4 Ω. Which one of the following statements is true.

(1) Rate of energy loss in the source is = 8 W

(2) Rate of energy conversion in the source is 16 W

(3) Power output in R is = 8 W

(4) Potential drop across R is = 16 V