An aromatic compound A of the molecular formula C₈H₁₀O on reaction with iodine and dilute NaOH gives a yellow precipitate. The structure of the compound is expected to be-

1. 

2. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CHOHCH}}_3$

3. 

4.  

In the following sequence :

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}\stackrel{\mathrm{NaCN}}{\to }\left(\mathrm{i}\right)\stackrel{\mathrm{Ni}/{\mathrm{H}}_2}{\to }\left(\mathrm{ii}\right)\stackrel{\mathrm{acetic} \mathrm{anhydride}}{\to }\left(\mathrm{iii}\right), \mathrm{product} \left(\mathrm{iii}\right) \mathrm{is}$

(1) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2$

(2) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CONHCH}}_3$

(3) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NHCOCH}}_3$

(4) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CONHCOCH}}_3$

Carbonyl compounds can generally be converted to hydrocarbons by :

1. H₂/Pt

2. LiAlH₄

3. ${\mathrm{N}}_2{\mathrm{H}}_4-\mathrm{KOH}/∆$

4. ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7-{\mathrm{H}}_2{\mathrm{SO}}_4$

Which statement about the aldol condensation is correct ?

(1) A Lewis acid is commonly used as a catalyst

(2) The initial step is probably the formation of a carbanion

(3) A Lewis base is employed to induce carbocation formation 

(4) The carbon chain is lengthened through the elimination of 1 mole of water

A compound gives a positive test with I₂/NaOH and is extracted from benzene by saturated NaHSO₃, It may be :

1. ${\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_4\mathrm{CHO}$

2. ${\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_3{\mathrm{COCH}}_3$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{COCH}}_2{\mathrm{CH}}_3$

4. ${\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_4{\mathrm{CH}}_2\mathrm{OH}$

Reactant (A) and (B) is:

(1) $\mathrm{Ph}-{\mathrm{CH}}_2-\mathrm{CH}=\mathrm{O} + {\mathrm{NH}}_2-\mathrm{OH}$

(2) $\mathrm{Ph}-\mathrm{CH}=\mathrm{O} + {\mathrm{NH}}_2-\mathrm{OH}$

(3) $\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CH}}_3 + {\mathrm{NH}}_2-{\mathrm{NH}}_2$

(4) $\mathrm{Ph}-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-{\mathrm{CH}}_3 + {\mathrm{NH}}_2-\mathrm{OH}$

${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{O}}{\mathrm{ll}}}{\mathrm{C}}-\mathrm{OH}\underset{∆}{\overset{\mathrm{Ca}{\left(\mathrm{OH}\right)}_2}{\to }}\left(\mathrm{A}\right)$

Product (A) is :

In which of the following compounds the methylenic hydrogens are the most acidic ?

(1) ${\mathrm{CH}}_3{\mathrm{COCH}}_2{\mathrm{CH}}_3$

_{(2) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{COOC}}_2{\mathrm{H}}_5$}

_{(3) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}{\left({\mathrm{COOC}}_2{\mathrm{H}}_5\right)}_2$}

_{(4) ${\mathrm{CH}}_3{\mathrm{COCH}}_2\mathrm{CN}$}

The presence of unsaturation in organic compounds can be tested with :

(1) Schiff's reagent

(2) Tollen's reagent

(3) Fehling's reagent

(4) Baeyer's reagent

Compound (A) C₆H₁₂O is optically active. Compound (A) give negative Tollens test and positive test with 2-4 dinitro phenyl hydrazine. Identify A.

(a) ${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{O}}{\parallel }}{\mathrm{C}}-{\mathrm{CH}}_2-\underset{\stackrel{\mathrm{l}}{{\mathrm{CH}}_3}}{\mathrm{CH}}-{\mathrm{CH}}_3$

(b) $$\begin{gathered} O \\ \left|\right| \\ C{H}_3—C—CH—C{H}_3 \\ | \\ C{H}_{2}C{H}_3 \end{gathered}$$

(c) $$\begin{gathered} O \\ \left|\right| \\ H —C—C{H}_2—CH—C{H}_3 \\ | \\ C{H}_2—C{H}_3 \end{gathered}$$

(d) ${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{O}}{\parallel }}{\mathrm{C}}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3$