What is compound Z?

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}\stackrel{\mathrm{NaCN}}{\to }$$\mathrm{X}\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }}$$\mathrm{Y}\underset{{\mathrm{H}}^{+}}{\overset{{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}}{\to }}$Z

(a) $O$
$\left|\right|$
$C{H}_{3}CH-CHCOH$           

(b) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CH}={\mathrm{NOCH}}_2{\mathrm{CH}}_3$

(c) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CH}({\mathrm{OCH}}_2{\mathrm{CH}}_3{)}_2$         

(d)  $O$
$\left|\right|$
$C{H}_{3}C{H}_{2}COC{H}_{2}C{H}_3$

Identify (A).

(a)      (b)     (c)      (d) 

$\underset{\left(\mathrm{i}\right){\mathrm{H}}^{+}}{\overset{\left(\mathrm{i}\right)\mathrm{KBrO},∆}{\to }} \left(\mathrm{X}\right)\stackrel{∆}{\to \left(\mathrm{Y}\right)}$

Hence the product (Y) in the above sequence of reactions, is :

(a)  (b)   (c)   (d) 

The action of bromine water (excess) on salicylic acid results in the formation of:-

(1) 

(2) 

(3) 

(4) 

An organic compound having the molecular formula C₈H₁₀O on being heated with I₂ and dilute NaOH gives a yellow precipitate. The expected compound is:

(a) C₆H₅CH₂CH₂OH

(b) 

(c) 

(d) 

The Birch reduction of benzoic acid gives:-
(a)  
(b)  
(c)  
(d) 

ph-CHO  +   2 $\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }$ major product of this reaction is:

(a) ph₃CH

(b) $OH$
$|$
$Ph-C-Ph$
$|$
$Ph$

(c) 

(d) ph₂CH₂

$\underset{\left(2\right) {\mathrm{H}}_3{\mathrm{O}}^{\oplus }}{\overset{\left(1\right) {\mathrm{KMnO}}_4, {\mathrm{HO}}^{-}, ∆}{\to }}$

The labelled carbon goes with:

$1. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{O}}_2\mathrm{H}$
$2. \stackrel{14}{\mathrm{C}}{\mathrm{O}}_2$
$3. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{H}}_2-{\mathrm{CO}}_2\mathrm{H}$
$4. \stackrel{14}{\mathrm{C}}{\mathrm{H}}_4$

Which of the following acid gives positive Tollen's reagent test.

(1) $({\mathrm{CH}}_2{)}_2{<}_{{\mathrm{CO}}_2\mathrm{H}}^{{\mathrm{CO}}_2\mathrm{H}}$           

(2) ${\mathrm{CH}}_2{<}_{{\mathrm{CO}}_2\mathrm{H}}^{{\mathrm{CO}}_2\mathrm{H}}$           

(3) $\underset{|}{\mathrm{C}}{\mathrm{O}}_2\mathrm{H}$
${\mathrm{CO}}_2\mathrm{H}$

(4) HCO₂H

Acetaldehyde and benzaldehyde can be differentiated by:

1. Fehling test

2. Iodoform test

3. Tollen's reagent

4. Both (1) and (2)