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Q. No.
Assertion (A):
There is a set of negatively charged basic proteins called Histone.
Reason (R):
Histone octamer is made of eight histone molecules.
1.
Both (A) and (R) are true and (R) is the correct explanation of (A).
2.
Both (A) and (R) are true but (R) is not the correct explanation of (A).
3.
(A) is true but (R) is false.
4.
(A) is false but (R) is true.
Subtopic: DNA Packaging |
80%
From NCERT
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Given below are statements on the structure of the DNA double helix.
1. The helix generally is wound clockwise.
2. purines and pyrimidines are paired by different numbers of hydrogen bonds.
3. The two strands run in parallel polarity.
4. The sugar in the DNA backbone is pentose sugar.
Which of the above statement/s is/are NOT TRUE?
1. Only 1.
2. Only 2.
3. Only 3.
4. Only 2 and 4.
1. The helix generally is wound clockwise.
2. purines and pyrimidines are paired by different numbers of hydrogen bonds.
3. The two strands run in parallel polarity.
4. The sugar in the DNA backbone is pentose sugar.
Which of the above statement/s is/are NOT TRUE?
1. Only 1.
2. Only 2.
3. Only 3.
4. Only 2 and 4.
Subtopic: DNA Double Helix |
74%
From NCERT
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The fact that a purine base always pairs through hydrogen bonds with a pyrimidine base in the DNA double helix leads to:
1. the anti-parallel nature.
2. the semi-conservative nature.
3. uniform width throughout the DNA.
4. uniform length in all DNA.
1. the anti-parallel nature.
2. the semi-conservative nature.
3. uniform width throughout the DNA.
4. uniform length in all DNA.
Subtopic: DNA Double Helix |
62%
From NCERT
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In the representation of the Central Dogma of Molecular Biology given below, identify P, Q and R.
1. P: ligase; Q: histone; R: polymerase
2. P: translation; Q: mRNA; R: transcription
3. P: splicing; Q: mRNA; R: capping
4. P: transcription: Q: mRNA; R: transcription
1. P: ligase; Q: histone; R: polymerase
2. P: translation; Q: mRNA; R: transcription
3. P: splicing; Q: mRNA; R: capping
4. P: transcription: Q: mRNA; R: transcription
Subtopic: DNA Double Helix |
69%
From NCERT
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The average Guanina content in yeast is found to be \(18 \%\).
Which of the following represents the nitrogenous base content percentages correctly from the above data?
1. \(\text { A: } 18 \% \text {; T: } 18 \% \text {; C: } 36 \%\)
2. \(\text { A: } 36 \% \text {; T: } 32 \% ; \text { C: } 32 \%\)
3. \(\text { A: } 32 \% \text {; T: } 32 \% \text {; C: } 18 \%\)
4. \(\text { A: 18%; T: 18%; C: 18%}\)
Which of the following represents the nitrogenous base content percentages correctly from the above data?
1. \(\text { A: } 18 \% \text {; T: } 18 \% \text {; C: } 36 \%\)
2. \(\text { A: } 36 \% \text {; T: } 32 \% ; \text { C: } 32 \%\)
3. \(\text { A: } 32 \% \text {; T: } 32 \% \text {; C: } 18 \%\)
4. \(\text { A: 18%; T: 18%; C: 18%}\)
Subtopic: The DNA |
89%
From NCERT
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Consider the following genetic code:
Which among the following would cause a frameshift mutation?
1. substitution of A by C in codon 2
2. insertion of G after C in codon 4
3. insertion of GCU after C in codon 6
4. deletion of codon 3, GAG
Which among the following would cause a frameshift mutation?
1. substitution of A by C in codon 2
2. insertion of G after C in codon 4
3. insertion of GCU after C in codon 6
4. deletion of codon 3, GAG
Subtopic: Genetic Code: III |
57%
From NCERT
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| Assertion (A): | RNA polymerases are able to catalyse all three steps of transcription. |
| Reason (R): | RNA polymerase contains an initiation factor and a termination factor in them. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Transcription: I |
From NCERT
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Which among the following statements about the exons is TRUE?
1. They are stop codons.
2. They are start codons.
3. They are coding sequences.
4. They are intervening sequences.
1. They are stop codons.
2. They are start codons.
3. They are coding sequences.
4. They are intervening sequences.
Subtopic: Transcription: I |
77%
From NCERT
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Study the given diagrammatic representation of Griffith's experiment to demonstrate the transformation in bacteria.
Select the option which is incorrectly representing the experiment:
1. (i) and (ii)
2. (ii) and (iii)
3. (iii) and (iv)
4. (ii) and (iv)
Select the option which is incorrectly representing the experiment:
1. (i) and (ii)
2. (ii) and (iii)
3. (iii) and (iv)
4. (ii) and (iv)
Subtopic: Search for Genetic Material |
90%
From NCERT
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| Assertion (A): | Primary transcripts in eukaryotes are non-functional. |
| Reason (R): | Methyl guanosine triphosphate is attached to 5' -end of hnRNA. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Subtopic: Transcription: IV |
62%
From NCERT
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