$\mathrm{Ph}-{\mathrm{CO}}_2\mathrm{H}\stackrel{{\mathrm{SOCl}}_2}{\to }\mathrm{A}\stackrel{{\mathrm{Me}}_2\mathrm{NH}}{\to }\mathrm{B}\stackrel{\left(\mathrm{c}\right)}{\to }\mathrm{Ph}-\mathrm{CHO}$, unknown reagent (c) is:

1. LiALH₄

2. NaBH₄

3. LiAlH₄(t-BuO)₃

4. PCC/CH₂CL₂

The product (B) in the above-mentioned reaction is:

1.		2.
3.		4.

$\stackrel{{\mathrm{Cl}}_2}{\to }$ (A), Product (A) of this reaction is:

(a) 

(b) 

(c) 

(d) 

; Product (B) of this reaction is :

1.		2.
3.		4.

Cyclopentadiene is much more acidic than cyclopentane, beacuse -

 The compounds among the following that can be generated by Friedel craft acylation is/are -

I.
II.
III.
IV.

     
The product B in the above-mentioned reaction is:

1.		2.
3.		4.

The major product obtained in the given reaction is:

1.		2.
3.		4.

The deactivating but ortho-para directing benzene ring substituent among the following is-

1. -N=O

2. -OCH₃

3. -COCH₃

4. -NO₂

Which of the following organic chlorides will not give a Friedel-Craft alkylation product when heated with benzene and AlCl₃/FeCl₃?