$\underset{{\mathrm{H}}_2{\mathrm{SO}}_4}{\overset{{\mathrm{HNO}}_3}{\to }}\left(\mathrm{A}\right)\underset{\mathrm{HCl}}{\overset{\mathrm{Zn}\left(\mathrm{Hg}\right)}{\to }}\left(\mathrm{B}\right),$Product (B) of this reaction is:

(a) 

(b) 

(c) 

(d) 

p-Toluidine reacts with benzene diazonium chloride to form compound, which on boiling with aq. H₂SO₄ give .......... products:
(1) 3
(2) 2
(3) 4
(4) 5

Product (C) in the above reaction is:

1. 

2.

3. 

4.

The product of the given reaction is :

; Product (B) of this reaction is :

1.		2.
3.		4.

Cyclopentadiene is much more acidic than cyclopentane, because:

 The compounds among the following that can be generated by Friedel craft acylation is/are -

I.
II.
III.
IV.

     
The product B in the above-mentioned reaction is:

1.		2.
3.		4.

The major product obtained in the given reaction is:

1.		2.
3.		4.

$\underset{\left(2\right) {\mathrm{H}}_3{\mathrm{O}}^{\oplus }}{\overset{\left(1\right) {\mathrm{KMnO}}_4, {\mathrm{HO}}^{-}, ∆}{\to }}$

The labelled carbon goes with:

$1. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{O}}_2\mathrm{H}$
$2. \stackrel{14}{\mathrm{C}}{\mathrm{O}}_2$
$3. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{H}}_2-{\mathrm{CO}}_2\mathrm{H}$
$4. \stackrel{14}{\mathrm{C}}{\mathrm{H}}_4$