From the given equation, certain conclusions are drawn.
\(\mathrm{E}=-2.178 \times 10^{-18} \mathrm{(J)} \frac{\mathrm{z}^2}{\mathrm{n}^2} \)$\mathrm{}$
Choose the incorrect statement:

1.	The negative sign in the equation implies that the energy of an electron bound to the nucleus is lower than it would be if the electron were at an infinite distance from the nucleus.
2.	The larger the value of n, the greater the orbit radius.
3.	The equation can be utilized to calculate the change in energy when the electron transitions between orbits.
4.	For n=1, the electron has a more negative energy than it does for n=6. This means that the electron is more loosely bound in the smallest allowed orbit.

The maximum number of electrons in a subshell with l = 3 and n = 4 is

1. 14

2. 16

3. 10

4. 12

The correct set of four quantum numbers for the valence electron of rubidium atom (Z =37) is

1. 5, 1, 1, +1/2               

2. 6, 0, 0, +1/2

3. 5, 0, 0, +1/2               

4. 5, 1, 0, +1/2

The total number of atomic orbitals in fourth energy level of an atom is

1. 16                                 

2. 32

3. 4                                   

4. 8

If the principal quantum number n=6, the correct sequence of filling of electrons will be:

Which one of the following ions has electronic configuration [Ar]3d⁶?

(At. no: Mn = 25, Fe = 26, Co = 27, Ni =28)

1. Ni³⁺               

2. Mn³⁺

3. Fe³⁺               

4. Co³⁺

Which one of the elements with the following outer orbital configurations may exhibit the

largest number of oxidation states ?

1. 3d³, 4s²

2. 3d⁵, 4s¹

3. 3d⁵, 4s²

4. 3d², 4s²

Maximum number of electrons in a subshell of an atom can be determined by which of the following formula :

1. 4l + 2

2. 2l + 1

3. 4l - 2

4. 2n²

Which of the following is not permissible arrangement of electrons in an atom?

1. n = 4, l = 0, m = 0, s = –1/2

2. n = 5, l = 3, m = 0, s = +1/2

3. n = 3, l = 2, m = –3, s = –1/2

4. n = 3, l = 2, m = –2, s = –1/2