The correct order of increasing bond length of
C-H, C-O, C-C and C=C is
1. C-C<C=C<C-O<C-H
2. C-O<C-H<C-C<C=C
3. C-H<C-O<C-C<C=C
4. C-H<C=C<C-O<C-C
Which of the following compounds has the lowest melting point?
1. CaBr2
2. CaI2
3. CaF2
4. CaCl2
Which of the following has the minimum bond length?
1.
2.
3. O2
4.
In which of the following pairs of molecules/ions, the central atoms have \(\mathrm{sp}^2\) hybridisation?
1. | \(\mathrm{NO}^-_2 ~\mathrm{and}~ \mathrm{NH}_3\) | 2. | \(\mathrm{BF}_3 ~\mathrm{and}~ \mathrm{NO}^-_2\) |
3. | \(\mathrm{NH}^-_2 ~\mathrm{and}~ \mathrm{H_2O}\) | 4. | \(\mathrm{BF}_3 ~\mathrm{and}~ \mathrm{NH}^-_2\) |
The correct increasing order of bond angles in the following species is:
1. | \(Cl_2O<ClO_2<ClO^-_2\) | 2. | \(ClO_2<Cl_2O<ClO^-_2\) |
3. | \(Cl_2O<ClO^-_2<ClO_2\) | 4. | \(ClO^-_2<Cl_2O<ClO_2\) |
The tendency of BF3, BCl3, and BBr3 to behave as Lewis acid decreases in the sequence
1. BCl3 > BF3 > BBr3
2. BBr3 > BCI3 > BF3
3. BBr3 > BF3 > BCl3
4. BF3 > BCl3 > BBr3
Given the following hydrocarbon:
The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively :
1. sp, sp3, sp2 and sp3
2. sp3, sp2, sp2 and sp
3. sp, sp2, sp2 and sp3
4. sp, sp2 sp3 and sp2
What is the dominant intermolecular force on bond that must be overcome in converting
liquid CH3OH to a gas?
1. Hydrogen bonding
2. Dipole-dipole interaction
3. Covalent bonds
4. London dispersion force
The angular shape of ozone molecule (O3) consists of
1. 1 sigma and 2 pi bonds
2. 2 sigma and 2 pi bonds
3. 1 sigma and 1 pi bonds
4. 2 sigma and 1 pi bonds
In the hydrocarbon
CH3-CH=CH-CH2-CCH
6 5 4 3 2 1
The state of hybridisation of carbons 1,3 and 5 are in the following sequence
(1) sp2, sp, sp3
(2) sp, sp3, sp2
(3) sp, sp2, sp3
(4) sp3, sp2, sp