A series combination of \(n_1\) capacitors, each of value \(C_1\), is charged by a source of potential difference \(4\) V. When another parallel combination of \(n_2\) capacitors, each of value \(C_2\), is charged by a source of potential difference \(V\), it has the same (total) energy stored in it as the first combination has. The value of \(C_2\) in terms of \(C_1\) is:
1. \(\frac{2C_1}{n_1n_2}\)
2. \(16\frac{n_2}{n_1}C_1\)
3. \(2\frac{n_2}{n_1}C_1\)
4. \(\frac{16C_1}{n_1n_2}\)

Subtopic:  Energy stored in Capacitor |
 72%
From NCERT
NEET - 2010
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 Consider the following two statements :

(1) Kirchhoff's junction law follows from the conservation of charge.

(2) Kirchhoff's loop law follows from the conservation of energy.

     Which of the following is correct?

(a) Both (A) and (B) are wrong

(b) (A) is correct and (B) is wrong

(3) (A)  is wrong and (B) is correct

(4) Both (A) and (B) are correct

Subtopic:  Kirchoff's Voltage Law |
 82%
From NCERT
NEET - 2010
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A wire of resistance \(12~\Omega \text{m}^{-1}\) is bent to form a complete circle of radius \(10~\text{cm}\). The resistance between its two diametrically opposite points, \(A\) and \(B\) as shown in the figure, is:

                         
1. \(0.6\pi~\Omega\)
2. \(3~\Omega\)
3. \(6\pi~\Omega\)
4. \(6~\Omega\)

Subtopic:  Combination of Resistors |
 58%
From NCERT
NEET - 2009
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A student measures the terminal potential difference \((V)\) of a cell (of emf \(\varepsilon \) and internal resistance \(r\)) as a function of the current \((I)\) flowing through it. The slope and intercept of the graph between \(V\) and \(I,\) then respectively, equal:
1. \(\varepsilon \) and \(-r\)
2. \(-r\) and \(\varepsilon \)
3.  \(r\) and \(-\varepsilon \)
4. \(-\varepsilon \) and \(r\)

Subtopic:  EMF & Terminal Voltage |
 66%
From NCERT
NEET - 2009
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A galvanometer having a coil resistance of 60Ω shows full scale deflection when a current of 1.0A passes through it. It can be converted into an ammeter to read currents upto 5.0A by 

(a) putting in series resistance of 240Ω

(b) putting in parallel resistance of 240Ω

(c) putting in series resistance of 15Ω

(d) putting in parallel resistance of 15Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 75%
From NCERT
NEET - 2009
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See the electrical circuit shown in this figure. Which of the following equation is a correct equation for it?

1. ε1-i1+i2R-i1r1=0

2. ε2-i2r2-ε1-i1r1=0

3. -ε2-i1+i2R+i2r2=0

4. ε1-i1+i2R+i1r1=0

Subtopic:  Kirchoff's Voltage Law |
 71%
From NCERT
NEET - 2009
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A current of 3A flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5Ω resistor is

 

(a) 4 W                                              (b) 2 W

(c) 1 W                                              (d) 5 W

Subtopic:  Heating Effects of Current |
 79%
From NCERT
NEET - 2008
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A wire of a certain material is streched slowly by ten per cent. Its new resistance and specific resistance become respectively 

(1) 1.2 times, 1.1 times

(2) 1.21 times,same 

(3) both remain the same

(4) 1.1 times, 1.1 times

Subtopic:  Derivation of Ohm's Law |
 83%
From NCERT
NEET - 2008
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A cell can be balanced against 110cm and 100 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is 

(1) 1.0 Ω

(2) 0.5 Ω

(3) 2.0 Ω

(4) zero 

Subtopic:  Grouping of Cells | Meter Bridge & Potentiometer |
 79%
From NCERT
NEET - 2008
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In the circuit shown, the current through the 4 Ω resistor is 1 A when the points P and M are connected to a DC voltage source. The potential difference  between the points M and N is 

1. 1.5 V 

2. 1.0 V

3. 0.5 V 

4. 3.2 V

Subtopic:  Kirchoff's Voltage Law |
 62%
From NCERT
NEET - 2008
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