The electric potential at a point (x,y,z) is given by 

            V=-x2y-xz3+4

The electric field E at that point is 

(a) E=i^2 xy+z3+j^x2+k^3xz2

(b) E=i^2xy+j^x2+y2+k^3xz-y2

(c) E=i^z3+j^xyz+k^z2

(d) E=i^2xy-z3+j^xy2+k^3z2x

Subtopic:  Relation between Field & Potential |
 78%
NEET - 2009
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The mean free path of electrons in a metal is 4×10-8m.The electric field which can give on an average 2 eV energy to an electron in the metal will be in a unit of Vm-1 :

(1) 8×107                             

(2) 5×10-11

(3) 8×10-11                         

(4) 5×107

Subtopic:  Relation between Field & Potential |
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Two dielectric slabs of constant \(K_1\) and \(K_2\) have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor? 


1. \(\frac{2\varepsilon_0A}{2}\left(K_1+K_2\right)\)
2. \(\frac{2\varepsilon_0A}{2}\frac{\left(K_1+K_2\right)}{K_1\times K_2}\)
3. \(\frac{2\varepsilon_0A}{d}\left(\frac{K_1+K_2}{K_1-K_2}\right)\)
4. \(\frac{2\varepsilon_0A}{d}\left(\frac{K_1\times K_2}{K_1+K_2}\right)\)

Subtopic:  Dielectrics in Capacitors |
 76%
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What is the equivalent capacitance between A and B in the given figure (all are in farad) 

(1) 1318F

(2) 4813F

(3) 131F

(4) 24071F

Subtopic:  Combination of Capacitors |
 79%
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\(100\) capacitors each having a capacity of \(10~\mu\text{F}\) are connected in parallel and are charged by a potential difference of \(100\) kV. The energy stored in the capacitors and the cost of charging them, if electrical energy costs \(108\) paise per kWh, will be?
1. \(10^{7}\) joule and \(300\) paise
2. \(5\times 10^{6}\) joule and \(300\) paise
3. \(5\times 10^{6}\) joule and \(150\) paise
4. \(10^7\) joule and \(150\) paise
Subtopic:  Energy stored in Capacitor |
 57%
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Four capacitors are connected as shown in the figure. Their capacities are indicated in the figure. The effective capacitance between points x and y is (in μF

(1) 56

(2) 76

(3) 83

(4) 2

Subtopic:  Combination of Capacitors |
 70%
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A 10 μF capacitor and a 20 μF capacitor are connected in series across a 200 V supply line. The charged capacitors are then disconnected from the line and reconnected with their positive plates together and negative plates together and no external voltage is applied. What is the potential difference across each capacitor 

(1) 4009V

(2) 8009V

(3) 400 V

(4) 200 V

Subtopic:  Combination of Capacitors |
 50%
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Two condensers C1 and C2 in a circuit are joined as shown in figure. The potential of point A is V1 and that of B is V2. The potential of point D will be 

(1) 12(V1+V2)

(2) C2V1+C1V2C1+C2

(3) C1V1+C2V2C1+C2

(4) C2V1C1V2C1+C2

Subtopic:  Combination of Capacitors |
 75%
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The combined capacity of the parallel combination of two capacitors is four times their combined capacity when connected in series. This means that 

(1) Their capacities are equal

(2) Their capacities are 1 μF and 2 μF

(3) Their capacities are 0.5 μF and 1 μF

(4) Their capacities are infinite

Subtopic:  Combination of Capacitors |
 75%
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In the given network capacitance, C1 = 10 μF, C2 = 5 μF and C3 = 4 μF. What is the resultant capacitance between A and B 

(1) 2.2 μF

(2) 3.2 μF

(3) 1.2 μF

(4) 4.7 μF

Subtopic:  Combination of Capacitors |
 87%
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