The kinetic energy of an electron with de-Broglie wavelength of 0.3 nanometer is 
(1) 0.168 eV           

(2) 16.8 eV

(3) 1.68 eV             

(4) 2.5 eV

Subtopic:  De-broglie Wavelength |
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The wavelength of de-Broglie wave is 2μm, then its momentum is (h = 6.63×10-34 J-s) 
(a) 3.315×10-28 kg-m/s            (b) 1.66×10-28 kg-m/s
(c) 4.97×10-28 kg-m/s              (d) 9.9×10-28 kg-m/s

Subtopic:  De-broglie Wavelength |
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Davission and Germer experiment proved

1. Wave nature of light               

2.  Particle nature of light

3. Both 1 and 2                       

4. Neither 1 nor 2

Subtopic:  Davisson & Germer Experiment (OLD NCERT) |
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If the kinetic energy of a free electron doubles, its de-Broglie wavelength changes by the factor 
(1) 12             

(2) 2

(3) 12                

(4) 2

Subtopic:  De-broglie Wavelength |
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The energy that should be added to an electron to reduce its de Broglie wavelength from one nm to 0.5 nm is

(1) Four times the initial energy

(2) Equal to the initial energy

(3) Twice the initial energy

(4) Thrice the initial energy

Subtopic:  De-broglie Wavelength |
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The wavelength of the matter wave is independent of

(1) Mass                 

(2) Velocity

(3) Momentum       

(4) Charge

Subtopic:  De-broglie Wavelength |
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The energy of a photon of wavelength λ is given by
1. hλ                      

2. chλ

3. λ/hc                   

4.  hc/λ

Subtopic:  De-broglie Wavelength |
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The rest mass of the photon is

(1) 0

(2)

(3) Between 0 and

(4) Equal to that of an electron

Subtopic:  Particle Nature of Light |
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The momentum of a photon of energy hv will be

(1) hv     

(2) hv/c

(3) hvc     

(4) h/v

Subtopic:  De-broglie Wavelength |
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If the momentum of a photon is p, then its frequency is

(1) phc           

(2) pch

(3) mhc           

(4) mch

where m is the rest mass of the photon

Subtopic:  De-broglie Wavelength |
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