The energy of a photon of wavelength $\mathrm{\lambda }$ is given by
1. h$\mathrm{\lambda }$                      

2. ch$\mathrm{\lambda }$

3. $\mathrm{\lambda }$/hc                   

4.  hc/$\mathrm{\lambda }$

The rest mass of the photon is

(1) 0

(2)$\infty$

(3) Between 0 and $\infty$

(4) Equal to that of an electron

The momentum of a photon of energy hv will be

(1) hv     

(2) hv/c

(3) hvc     

(4) h/v

If the momentum of a photon is p, then its frequency is

(1) $\frac{\mathrm{ph}}{\mathrm{c}}$           

(2) $\frac{\mathrm{pc}}{\mathrm{h}}$

(3) $\frac{\mathrm{mh}}{\mathrm{c}}$           

(4) $\frac{\mathrm{mc}}{\mathrm{h}}$

where m is the rest mass of the photon

An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW, then the number of photons radiated per second is

(1) $1.5\times {10}^{29}$             

(2) $1.5\times {10}^{31}$

(3) $1.5\times {10}^{33}$             

(4) $1.5\times {10}^{35}$

The energy of a photon is E = hv and the momentum of photon $\mathrm{p}=\frac{\mathrm{h}}{\mathrm{\lambda }}$, then the velocity of photon will be

(1) E/p                     

(2) Ep

(3)  ${\left(\frac{\mathrm{E}}{\mathrm{P}}\right)}^2$                 

(4) $3\times {10}^8 \mathrm{m}/\mathrm{s}$

The approximate wavelength of a photon of energy 2.48 eV is 
(1) 500 Å                   

(2) 5000 Å

(3) 2000 Å                   

(4) 1000 Å

The energy of a photon of light with wavelength 5000 Å is approximately 2.5 eV. This way the energy of an X-ray photon with wavelength 1Å would be 
(1) 2.5/5000 eV             

(2) $2.5/{\left(5000\right)}^2 \mathrm{eV}$

(3) $2.5\times 5000 \mathrm{eV}$           

(4)  $2.5\times {\left(5000\right)}^2 \mathrm{eV}$