A certain current liberates 0.504 g of hydrogen in 2 hr. How many gram of copper can be liberated by the same current flowing for the same time in CuSO4 solution?

1. 12.7

2. 16

3. 31.8

4. 63.5

Subtopic:  Faraday’s Law of Electrolysis |
 66%
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What happens to the voltage in a galvanic cell when the salt bridge is removed?

1. The voltage drops to zero.
2. The voltage remains the same.
3. The voltage gradually increases.
4. The voltage rapidly increases.

Subtopic:  Batteries & Salt Bridge |
 78%
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A depolariser used in dry cell batteries is: 

1. Ammonium chloride 

2. Manganese dioxide

3. Potassium hydroxide 

4. Sodium phosphate

Subtopic:  Batteries & Salt Bridge |
 53%
From NCERT
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If an iron rod is dipped in CuSO4 solution, then:

1. Blue colour of the solution turns red.

2. Brown layer is deposited on iron rod.

3. No change occurs in the colour of the solution.

4. None of the above.

Subtopic:  Electrochemical Series |
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When NaCl solution is electrolysed using Pt electrodes then pH of solution

1. Increases

2. Decreases

3. Remains same

4. Firstly increases and then decreases

Subtopic:  Relation between Emf, G, Kc & pH |
 62%
From NCERT
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The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
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Electrolysis of hot aqueous solution of NaCl gives NaClO4 as-

NaCl +4H2O           NaClO4 + 4H2

How many faraday are required to obtain 1000 g of sodium perchlorate ?

(1) 66 F

(2) 122.5 F

(3) 15.13 F

(4) 1.86 F

Subtopic:  Faraday’s Law of Electrolysis |
 60%
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A button cell used in watches functions as following

Zn(s) + Ag2O(s) + H2O (l) 2Ag(s) + Zn2+(aq) + 2OH-(aq)

If half cell potentials are

Zn2+aq +2e-  Znx; Eo = -0.76VAg2Os + H2Ol + 2e-  2Ags + 2OH-aq; Eo = 0.34V

The cell potential will be

1. 0.84 V

2. 1.34 V

3. 1.10 V

4. 0.42 V

 

 

Subtopic:  Electrolytic & Electrochemical Cell |
 82%
From NCERT
NEET - 2013
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Limiting molar conductivity of NH4OH (i.e Åm(NH4OH)) is equal to:-

1. Åm (NH4Cl)+Åm(NaCl)-Åm(NaOH) 

2. Åm(NaOH)+Åm(NaCl)-Åm(NH4Cl)

3. Åm(NH4OH)+Åm(NH4Cl)-Åm(HCl)

4. Å(NH4Cl)+Å(NaOH)-Å(NaCl)

Subtopic:   Kohlrausch Law & Cell Constant |
 83%
From NCERT
NEET - 2012
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The efficiency of a fuel cell is given by:

(a) H/G                      (b) G/S
(c) G/H                      (d) S/G

Subtopic:  Hydrogen Economy |
 67%
NEET - 2007
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