The mass of an $\mathrm{\alpha }$-particle is:

1.	less than the sum of masses of two protons and two neutrons.
2.	equal to the mass of four protons.
3.	equal to the mass of four neutrons.
4.	equal to the sum of masses of two protons and two neutrons.

Atomic number of a nucleus is Z and atomic mass is M. The number of neutron is

(1) M-Z           

(2) M

(3) Z               

(4) M+Z 

The $\mathrm{\alpha }$-particle is the nucleus of an atom of

(1) Neon             

(2) Hydrogen

(3) Helium           

(4) Deuterium

The force acting between proton and proton inside the nucleus is 

(1) Coulombic             

(2) Nuclear

(3) Both                       

(4) None of these

For a nucleus to be stable, the correct relation between neutron number N and Proton number Z is

(1) N > Z             

(2) N = Z 

(3) N < Z             

(4) N$\ge$Z

${\mathrm{M}}_{\mathrm{n}}$ and ${\mathrm{M}}_{\mathrm{P}}$ represent mass of neutron and proton respectively. If an element having atomic mass M has N-neutron and Z-proton, then the correct relation will be

(1) $\mathrm{M}<\left[{\mathrm{NM}}_{\mathrm{n}}+{\mathrm{ZM}}_{\mathrm{p}}\right]$         

(2) $\mathrm{M}>\left[{\mathrm{NM}}_{\mathrm{n}}+{\mathrm{ZM}}_{\mathrm{p}}\right]$

(3) $\mathrm{M}=\left[{\mathrm{NM}}_{\mathrm{n}}+{\mathrm{ZM}}_{\mathrm{p}}\right]$         

(4) $\mathrm{M}=\mathrm{N}\left[{\mathrm{M}}_{\mathrm{n}}+{\mathrm{M}}_{\mathrm{p}}\right]$

If a ${\mathrm{H}}_2$ nucleus is completely converted into energy, the energy produced will be around

(1) 1 MeV               

(2) 938 MeV

(3) 9.38 MeV           

(4) 238 MeV

As compared ${}_{12}\mathrm{C}$ atom, ${}_{14}\mathrm{C}$ atom has

(1) Two extra protons and two extra electrons

(2) Two extra protons but no extra electrons

(3) Two extra neutrons and no extra electrons

(4) Two extra neutrons and two extra electrons

If m, ${\mathrm{m}}_{\mathrm{n}}$ and ${\mathrm{m}}_{\mathrm{p}}$ are the masses of ${}_{\mathrm{Z}}\mathrm{X}_{\mathrm{A}}$ nucleus, neutron and proton respectively 

(1) $\mathrm{m}<\left(\mathrm{A}-\mathrm{Z}\right){\mathrm{m}}_{\mathrm{n}}+{\mathrm{Zm}}_{\mathrm{p}}$       

(2) $\mathrm{m}=\left(\mathrm{A}-\mathrm{Z}\right){\mathrm{m}}_{\mathrm{n}}+{\mathrm{Zm}}_{\mathrm{p}}$

(3) $\mathrm{m}=\left(\mathrm{A}-\mathrm{Z}\right){\mathrm{m}}_p+{\mathrm{Zm}}_{\mathrm{n}}$        

(4) $\mathrm{m}>\left(\mathrm{A}-\mathrm{Z}\right){\mathrm{m}}_{\mathrm{n}}+{\mathrm{Zm}}_{\mathrm{p}}$

On the bombardment of neutron with Boron. $\mathrm{\alpha }$-particle is emitted and product nuclei formed is

(1) ${}_6\mathrm{C}_{{}_{12}}$         

(2) ${}_3\mathrm{Li}_6$

(3) ${}_3\mathrm{Li}_7$           

(4) ${}_4\mathrm{Be}_9$