The length of a potentiometer wire is l. A cell of emf E is balanced at a length l/3 from the positive end of the wire. If the length of the wire is increased by l/2. At what distance will be the same cell give a balance point.

1.  2l/3

2.  l/2

3.  l/6

4.  4l/3

 54%
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A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite directions. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of the emf of the two cells is:
1. 5 : 4
2. 3 : 4
3. 3 : 2
4. 5 : 1
 68%
From NCERT
NEET - 2016
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\({A, B}~\text{and}~{C}\) are voltmeters of resistance \(R,\) \(1.5R\) and \(3R\) respectively as shown in the figure above. When some potential difference is applied between \({X}\) and \({Y},\) the voltmeter readings are \({V}_{A},\) \({V}_{B}\) and \({V}_{C}\) respectively. Then:

        

1. \({V}_{A} ={V}_{B}={V}_{C}\) 2. \({V}_{A} \neq{V}_{B}={V}_{C}\)
3. \({V}_{A} ={V}_{B}\neq{V}_{C}\) 4. \({V}_{A} \ne{V}_{B}\ne{V}_{C}\)

Subtopic:  Kirchoff's Voltage Law |
 65%
From NCERT
NEET - 2015
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The figure given below shows a circuit when resistances in the two arms of the meter bridge are \(5~\Omega\) and \(R\), respectively. When the resistance \(R\) is shunted with equal resistance, the new balance point is at \(1.6l_1\). The resistance \(R\) is:

1. \(10~\Omega\) 2. \(15~\Omega\)
3. \(20~\Omega\) 4. \(25~\Omega\)
Subtopic:  Meter Bridge |
 73%
From NCERT
AIPMT - 2014
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A wire of resistance \(4~\Omega\) is stretched to twice its original length. The resistance of a stretched wire would be:
1. \(4~\Omega\)
2. \(8~\Omega\)
3. \(16~\Omega\)
4. \(2~\Omega\)
Subtopic:  Derivation of Ohm's Law |
 84%
From NCERT
AIPMT - 2013
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Given below two statements:
Statement I: Kirchhoff’s junction law follows the conservation of charge. 
Statement II: Kirchhoff’s loop law follows the conservation of energy.
 
1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect and Statement II is correct.
4. Both Statement I and Statement II are correct.
Subtopic:  Kirchoff's Current Law |
 84%
From NCERT
AIPMT - 2010
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A student measures the terminal potential difference \(V\) of a cell (of emf \( E\) and internal resistance \(R\)) as a function of the current \(I\) flowing through it. The slope and intercept of the graph between \(V\) and \(I,\) respectively, is equal to:
1. \(E\) and \(-r\)
2. \(-r\) and \(E\)
3. \(r\) and \(-E\)
4. \(-E\) and \(r\)
Subtopic:  EMF & Terminal Voltage |
 70%
From NCERT
AIPMT - 2009
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A cell can be balanced against 100 cm and 110 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is:

1.  1.0 Ω

2.  0.5 Ω

3.  2.0 Ω

4.  zero

 75%
From NCERT
AIPMT - 2008
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Find equivalent resistance between \(X\) and \(Y\):
  

1. \(R\)

2. \(R/L\)

3. \(2R\)

4. \(5R\)

Subtopic:  Combination of Resistors |
 66%
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A current of \(1.6\) A is passed through a solution of CuSO4. How many Cu++ ions are liberated in one minute? (Electronic charge= \(1.6\times10^{-19}\) C)
1. 3 × 1020
2. 3 × 1010
3. 6 × 1020
4. 6 × 1010

Subtopic:  Current & Current Density |
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