The figure given below shows a circuit when resistances in the two arms of the meter bridge are \(5~\Omega\) and \(R\), respectively. When the resistance \(R\) is shunted with equal resistance, the new balance point is at \(1.6l_1\). The resistance \(R\) is:
1. | \(10~\Omega\) | 2. | \(15~\Omega\) |
3. | \(20~\Omega\) | 4. | \(25~\Omega\) |
Statement I: | Kirchhoff’s junction law follows the conservation of charge. |
Statement II: | Kirchhoff’s loop law follows the conservation of energy. |
1. | Both Statement I and Statement II are incorrect. |
2. | Statement I is correct but Statement II is incorrect. |
3. | Statement I is incorrect and Statement II is correct. |
4. | Both Statement I and Statement II are correct. |
A cell can be balanced against 100 cm and 110 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is:
1. 1.0 Ω
2. 0.5 Ω
3. 2.0 Ω
4. zero
Find equivalent resistance between \(X\) and \(Y\):
1. \(R\)
2. \(R/L\)
3. \(2R\)
4. \(5R\)
A current of \(1.6\) A is passed through a solution of CuSO4. How many Cu++ ions are liberated in one minute? (Electronic charge= \(1.6\times10^{-19}\) C)
1. 3 × 1020
2. 3 × 1010
3. 6 × 1020
4. 6 × 1010
\({A, B}~\text{and}~{C}\) are voltmeters of resistance \(R,\) \(1.5R\) and \(3R\) respectively as shown in the figure above. When some potential difference is applied between \({X}\) and \({Y},\) the voltmeter readings are \({V}_{A},\) \({V}_{B}\) and \({V}_{C}\) respectively. Then:
1. | \({V}_{A} ={V}_{B}={V}_{C}\) | 2. | \({V}_{A} \neq{V}_{B}={V}_{C}\) |
3. | \({V}_{A} ={V}_{B}\neq{V}_{C}\) | 4. | \({V}_{A} \ne{V}_{B}\ne{V}_{C}\) |
The length of a potentiometer wire is l. A cell of emf E is balanced at a length l/3 from the positive end of the wire. If the length of the wire is increased by l/2. At what distance will be the same cell give a balance point.
1. 2l/3
2. l/2
3. l/6
4. 4l/3