The existence of two different coloured complexes with the composition of [Co(NH3)4Cl2]+is due to:
1. Linkage isomerism
2. Geometrical isomerism
3. Coordination isomerism
4. Ionisation isomerism
Which of the following ions doesn't exhibit optical isomerism?
(en = ethylenediamine)
1. [Co(en)2Cl2]+
2. [Co(NH3)3Cl3]
3. [Co(en)Cl2(NH3)2]+
4. [Co(en)3]3+
A complex ion among the following can absorb visible light is:
(At. no. Zn = 30, Sc = 21, Ti = 22, Cr = 24)
1. [Sc(H2O)3(NH3)3]3+
2. [Ti(en)2 (NH3)2]4+
3. [Cr(NH3)6]3+
4. [Zn(NH3)6]2+
Out of , , Cu2Cl2 and (Z of Ti = 22, Co=27, Cu = 29, Ni= 28) the colourless species are:
1.
2.
3.
4.
Which of the following complexes has the highest paramagnetic behaviour?
(where gly = glycine, en = ethylenediamine, ox = oxalate ion and bpy = bipyridyl moieties )
(At no : Ti= 22, V = 23, Fe = 26, Co = 27)
1. [V(gly)2(OH)2(NH3)2]+
2. [Fe(en)(bpy)(NH3)2]2+
3. [Co(ox)2(OH)2]-
4. [Ti(NH3)6]3+
CFSE (in the octahedral field) will be maximum in:
(Atomic number Co = 27)
1.
2.
3.
4.
The compound that gives a pair of enantiomorphs is:
(en = NH2 CH2CH2 NH2)
1.
2.
3.
4.
A pair that contains both the ions coloured in an aqueous solution is:
(At. no. : Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)
1. | \(N i^{2+}, T i^{3+} \) | 2. | \(S c^{3+}, T i^{3+} \) |
3. | \(\mathrm{Sc}^{3+}, \mathrm{Co}^{2+} \) | 4. | \(\mathrm{Ni}^{2+}, \mathrm{Cu}^{+}\) |
[Co(NH3)4(NO2)2]Cl exhibits:
1. | linkage isomerism, ionization isomerism, and optical isomerism |
2. | linkage isomerism, ionization isomerism, and geometrical isomerism |
3. | ionization isomerism, geometrical isomerism, and optical isomerism |
4. | linkage isomerism, geometrical isomerism, and optical isomerism |
[Cr(H2O)6]Cl3 (At. No. of Cr = 24) has a magnetic moment of 3.83 BM.
The correct distribution of 3d electrons in the chromium of the complex is:
1.
2.
3.
4.