Light travels faster in the air than in glass. This is in accordance with:

1. the wave theory of light.
2. the corpuscular theory of light.
3. neither (1) nor (2)
4. both (1) and (2)
Subtopic:  Huygens' Principle |
 58%
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Soap bubble appears coloured due to the phenomenon of:
1. Interference
2. Diffraction
3. Dispersion
4. Reflection

Subtopic:  Superposition Principle |
 55%
From NCERT
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By Huygen's wave theory of light, we cannot explain the phenomenon of:

1. Interference
2. Diffraction
3. Photoelectric effect
4. Polarisation

Subtopic:  Huygens' Principle |
 73%
From NCERT
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Huygens' wave theory allows us to know the:

1. Wavelength of the wave.
2. Velocity of the wave.
3. Amplitude of the wave.
4. Propagation of wavefront.

Subtopic:  Huygens' Principle |
 84%
From NCERT
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Huygen's principle for secondary wavelets may be used to:

1. explain Snell's law.
2. find the velocity of light in vacuum.
3. find a new position of a wavefront.
4. both (1) & (3) are correct.

Subtopic:  Huygens' Principle |
 70%
From NCERT
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When the light diverges from a point source, the shape of the wavefront is:
1. Parabolic.
2. Plane.
3. Spherical.
4. Elliptical.

Subtopic:  Huygens' Principle |
 83%
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Two slits in Young's experiment have widths in the ratio of \(1:25\). The ratio of intensity at the maxima and minima in the interference pattern \(\frac{I_{\text{max}}}{I_{\text{min}}}\) is:
1. \(\dfrac{9}{4}\) 2. \(\dfrac{121}{49}\)
3. \(\dfrac{49}{121}\) 4. \(\dfrac{4}{9}\)
Subtopic:  Young's Double Slit Experiment |
 74%
From NCERT
NEET - 2015
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If an interference pattern has maximum and minimum intensities in a \(36:1\) ratio, then what will be the ratio of their amplitudes?
1. \(5:7\)
2. \(7:4\)
3. \(4:7\)
4. \(7:5\)

Subtopic:  Superposition Principle |
 81%
From NCERT
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Two superposing waves are represented by the following equations: 
\(y_1=5 \sin 2 \pi(10{t}-0.1 {x}), {y}_2=10 \sin 2 \pi(10{t}-0.1 {x}).\)
Ratio of intensities \(\frac{I_{max}}{I_{min}}\) will be:
1. \(1\)
2. \(9\)
3. \(4\)
4. \(16\)

Subtopic:  Superposition Principle |
 85%
From NCERT
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On superposition of two waves \(y_{1}=3\sin\left ( \omega t-kx \right )\) and \(y_{2}=4\sin\left ( \omega t-kx+\frac{\pi }{2} \right )\) at a point, the amplitude of the resulting wave will be:
1. \(7\)
2. \(5\)
3. \(\sqrt{7}\)
4. \(6.5\)

Subtopic:  Superposition Principle |
 85%
From NCERT
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