Which compounds will not reduce Fehling's solution?

1. Methanal                                 

2. Ethanal

3. Trichloroethanal                       

4. Benzaldehyde

 

Fehling's solution is:

1. Acidified copper sulphate solution

2. Ammoniacal cuprous chloride solution

3. Copper sulphate, Rochelle salt + NaOH

4. None of the above

Benzaldehyde and acetaldehyde can be distinguished by:

1. Iodoform test

2. 2:4 DNP test

3. ${\mathrm{NH}}_3$ reaction

4. Wolff-Kishner's reduction

The conversion of CH₃OH to CH₃COOH can be brought in by:

1. K₂Cr₂O₇/H⁺                           

2. CO + Rh

3. KMnO₄                                   

4. H₃PO₄

Polarisation of electrons in acrolein may be written as             

1. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\mathrm{CH}=\stackrel{\mathrm{\delta }-}{\mathrm{O}}$

2. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{}{\mathrm{O}}$

3. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{\delta +}{\mathrm{O}}$

4. $\stackrel{\mathrm{\delta }-}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}=\mathrm{O}$

Dry distillation of barium salt of Hexane-1,2-dicarboxylic acid gives:

1. 

2. 

3. 

4. 

Ethyl ester $\underset{\mathrm{Excess}}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$ P.

The product P will be

1.		2.
3.		4.

RCOOH $\to$RCH₂OH. This mode of reduction of an acid to alcohol can be affected only by:

1. Zn/HCl

2. Na-alcohol

3. aluminium isopropoxide and isopropyl alcohol

4. LiAlH₄

Compound (A) C₅H₁₀O forms a phenyl hydrazone and gives negative Tollen's and iodoform tests. Also, compound (A) on reduction gives n-pentane. Compound (A) is-

Formaldehyde can be distinguished from acetaldehyde by:

1. Fehling's solution                     

2. Schiff's reagent

3. Ammonia                               

4. Ammoniacal ${\mathrm{AgNO}}_3$