In eukaryotes the gene expression is regulated at:

A. Transcriptional level

B. Processing level

C. Transport of mRNA from nucleus to the cytoplasm

D. Translational level

1. A, C               

2. A, B, C, D                 

3. B, C, D                     

4. A, B, C

In prokaryotes, gene regulation occurs at the level of:

1. Transcription                               

2. Translation

3. Post transcription                         

4. Post translation

A. DNA polymorphism plays important role in evolution and speciation.

B. 99.9% nucleotides bases are exactly same in all people

C. Chromosome 1 has the fewest genes (23) and Y-chromosomes has most genes (2968)

D. BAC and YAC have been used in Human Genome Project.

1. All correct                   

2. All incorrect

3. A, B, D are correct       

4. B, C, D are correct

Go through the following diagram of Nucleosome (structural unit of chromatin). Identify its componential parts indicated by A, B and C:

Following is the schematic structure of transcription unit having some important components indicated by A, B, C, D and E. In which of four option the components are identified correctly:

The fact that the genetic code is almost universal in living organisms is considered to be evidence that all organisms:

1. Are evolutionarily related

2. Are genetically identical

3. Have the same sequence of anticodons

4. None of the above

In the following diagram of the lac operon, an operon for inducible enzymes, identify components and enzymes:

Alfred Hershey and Martha Chase made a big contribution in proving DNA role as the hereditary molecule. The experiment is shown in the diagram. A and C are the presence or absence of radioactivity detected in cells B and D are the presence or absence of radioactivity detected in supernatants cells. Identify A, B, C and D:

1. A - No Radioactivity (35S) detected in cells; B - Radioactivity (32P) detected in supernatant; C - Radioactivity (35S) detected in cells; D - No Radioactivity in supernatant

2. A- Radioactivity (35S) detected in cells; B - No Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant

3. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant

4. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - No Radioactivity (32P) detected in cells; D - Radioactivity in supernatant

If the DNA of this virus was labeled with 32P and the protein of the virus was labeled with 35S, which molecule(s) would be present inside the cells?

1. 35S and 32P

2. 35S only

3. 32P only

4. Neither molecule would be present inside the cell

The prediction of sequence of amino acid is _____A ____ if the sequence of nucleotides mRNA is known. The prediction of sequence of nucleotide in concerned mRNA is ____B____ because the genetic code is _____C_____:

1. A - possible, B - impossible, C - universal

2. A - possible, B - impossible, C - degenerate

3. A - impossible, B - possible, C - universal

4. A - impossible, B - possible, C - degenerate