If the electronic configuration of an element is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{2}4{\mathrm{s}}^2$, the four electrons that participate in the chemical bond formation will be from :

1.	$3{\mathrm{p}}^6$	2.	$3{\mathrm{p}}^6, 4{\mathrm{s}}^2$
3.	$3{\mathrm{p}}^6, 3{\mathrm{d}}^2$	4.	$3{\mathrm{d}}^2, 4{\mathrm{s}}^2$

The correct bond angle for \(\mathrm{sp}^2\) hybridization is:
1. \(90^\circ\)
2. \(120^\circ\)
3. \(180^\circ\)
4. \(109^\circ\)

The electronic configurations of the elements A, B, and C are given below.

$\mathrm{A} = 1{\mathrm{s}}^2 2{\mathrm{s}}^2 2{\mathrm{p}}^6$
$\mathrm{B} = 1{\mathrm{s}}^2 2{\mathrm{s}}^2 2{\mathrm{p}}^6 3{\mathrm{s}}^2 3{\mathrm{p}}^3$
$\mathrm{C} = 1{\mathrm{s}}^2 2{\mathrm{s}}^2 2{\mathrm{p}}^6 3{\mathrm{s}}^2 3{\mathrm{p}}^5$

The stable form of A may be represented by the formula:

Among the following, the correct order of energies of molecular orbitals of N₂ is:

1. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)<\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)<(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

2. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)>\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)>(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

3. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)<\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

4. $\left(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}\right)>\left(\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}\right)<(\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{x}})\approx (\mathrm{\pi }*2{\mathrm{p}}_{\mathrm{y}})$

From the perspective of molecular orbital theory, which statement is false?

The shape of  AsF₅ is:
1. Pentagonal bipyramidal.
2. Trigonal bipyramidal.
3. Distorted tetrahedral.
4. Square pyramidal.

The incorrect statement about NH₃ and H₂O is :

1. The bond angle in NH₃ is less than in H₂O.

2. Both have distorted tetrahedral geometries.

3. The bond angle in H₂O is less than in NH₃.

4. Both are sp³ hybridized. 

The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -

The plus and negative sign of the orbitals mean:

1. Wave function.

2. Probability density.

3. Quantum number of orbitals.

4. Frequency of orbitals.

${\mathrm{AlCl}}_3$ $+$ ${\mathrm{Cl}}^{-}$ $\to$ ${\mathrm{AlCl}}_4^{-}$

The change in the hybridization of the Al atom in the above reaction is:
1. \(s p^{2} \text { to } s p^{3}\)
2. \(\mathrm{sp}^{3} \text { to } s p^{2}\)
3. \(\mathrm{sp}^{3} \text { to } \mathrm{dsp}{ }^{2}\)
4. \(\operatorname{sp}^{2} \text { to } d s p^{2}\)