$\mathrm{Ph}-{\mathrm{CO}}_2\mathrm{H}\stackrel{{\mathrm{SOCl}}_2}{\to }\mathrm{A}\stackrel{{\mathrm{Me}}_2\mathrm{NH}}{\to }\mathrm{B}\stackrel{\left(\mathrm{c}\right)}{\to }\mathrm{Ph}-\mathrm{CHO}$, unknown reagent (c) is:

1. LiALH₄

2. NaBH₄

3. LiAlH₄(t-BuO)₃

4. PCC/CH₂CL₂

The product (B) in the above-mentioned reaction is:

1.		2.
3.		4.

In the above reaction o/p ratio will be highest when:-
(1) R=-CH₃
(2) R=-CH₂-CH₃
(3) R=-CHMe₂
(4) R=-CMe₃

$\stackrel{{\mathrm{Cl}}_2}{\to }$ (A), Product (A) of this reaction is:

(a) 

(b) 

(c) 

(d) 

 $\underset{{\mathrm{H}}_2{\mathrm{SO}}_4}{\overset{{\mathrm{HNO}}_3}{\to }}\left(\mathrm{A}\right)\underset{\mathrm{HCl}}{\overset{\mathrm{Zn}\left(\mathrm{Hg}\right)}{\to }}\left(\mathrm{B}\right),$Product (B) of this reaction is:

(a) 

(b) 

(c) 

(d) 

p-Toluidine reacts with benzene diazonium chloride to form compound, which on boiling with aq. H₂SO₄ give .......... products:
(1) 3
(2) 2
(3) 4
(4) 5

Product (C) in the above reaction is:

1. 

2.

3. 

4.

The product of the given reaction is :

; Product (B) of this reaction is :

1.		2.
3.		4.

Cyclopentadiene is much more acidic than cyclopentane, because: