A partricle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be
(1)β2/α2
(2)α/β
(3)β2/α
(4)2πβ/α
1. | simple harmonic motion of frequency \(\frac{\omega}{\pi}\). |
2. | simple harmonic motion of frequency \(\frac{3\omega}{2\pi}\). |
3. | non-simple harmonic motion. |
4. | simple harmonic motion of frequency \(\frac{\omega}{2\pi}\). |
A point performs simple harmonic oscillation of period T and the equation of motion is given by x= a sin .After the elapse of what fraction of the time period the velocity of the point will be equal to half to its maximum velocity?
(1)
(2)
(3)
(4)
The angular velocities of three bodies in simple harmonic motion are with their respective amplitudes as . If all the three bodies have same mass and maximum velocity, then
(a) (b)
(b) (d)
The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes will be
(1)
(2)
(3) 1 cm
(4) 2 cm
The maximum velocity of a simple harmonic motion represented by is given by
(1) 300
(2)
(3) 100
(4)
The displacement equation of a particle is The amplitude and maximum velocity will be respectively
(a) 5, 10
(b) 3, 2
(c) 4, 2
(d) 3, 4
The instantaneous displacement of a simple pendulum oscillator is given by . Its speed will be maximum at time
(1)
(2)
(3)
(4)