The output \((X)\) of the logic circuit shown in the figure will be: 
  
1. \(X= \overline{A\cdot B}\)
2. \(X = A\cdot B\)
3. \(X= \overline{A+ B}\)
4. \(X=\overline{\overline{A}} \cdot \overline{\overline{B}}\)

Subtopic:  Logic gates |
 77%
From NCERT
AIPMT - 2013
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Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is:
    
1. \(0.75~\text{A}\)
2. zero
3. \(0.25~\text{A}\)
4. \(0.5~\text{A}\)

Subtopic:  PN junction |
 86%
From NCERT
AIPMT - 2012
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Transfer characteristics [output voltage (Vo) vs input voltage (Vi)] for a base biased transistor in CE configurations are as shown in the figure. For using the transistor as a switch, it is used:

1. In region III

2. Both in the region (I) and (III)

3. In region II

4. In region I

Subtopic:  Transistor (OLD NCERT) |
 78%
From NCERT
AIPMT - 2012
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The symbolic representation of four gates is shown as: 
   
Pick out which ones are for AND, NAND, and NOT gates, respectively.

1.  (i), (iv), and (iii)

2.  (ii), (iii), and (iv)

3.  (ii), (iv), and (iii)

4.  (ii), (iv), and (i)

Subtopic:  Logic gates |
 88%
From NCERT
AIPMT - 2011
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A transistor is operated in a common emitter configuration at Vc =2 V such that a change in the base current from 100 μA to 300 μA produces a change in the collector current from 10 mA to 20mA. The current gain is:

1.  75

2.  100 

3.  25

4.  50

Subtopic:  Transistor (OLD NCERT) |
 76%
From NCERT
AIPMT - 2011
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A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω and an output impedance of 200 Ω. The power gain of the amplifier is:

1. 500

2. 1000

3. 1250

4. 50

Subtopic:  Applications of Transistor (OLD NCERT) |
 72%
From NCERT
AIPMT - 2010
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To get an output Y = 1 from the circuit shown below, the input must be:

 

1. A=0 B=1 C=0

2. A=0 B=0 C=1

3. A=1 B=0 C=1

4. A=1 B=0 C=0

Subtopic:  Logic gates |
 91%
From NCERT
AIPMT - 2010
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\(\mathrm{p\text-n}\) photodiode is fabricated from a semiconductor with a band gap of \(2.5\) eV. It can detect a signal of wavelength:
1. \(6000~\mathring{A}\)
2. \(4000\) nm
3. \(6000\) nm
4. \(4000~\mathring{A}\)  
Subtopic:  Energy Band theory |
 63%
From NCERT
AIPMT - 2009
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The circuit is equivalent to: 
     

1. AND gate
2. NAND gate
3. NOR gate
4. OR gate

Subtopic:  Logic gates |
 75%
From NCERT
AIPMT - 2008
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In the following circuit, the output \(Y\) for all possible inputs \(A\) and \(B\) is expressed by the truth table: 
    

1. A B Y 2. A B Y
0 0 0 0 0 1
0 1 0 0 1 1
1 0 0 1 0 1
1 1 1 1 1 0
3. 0 0 1 4. 0 0 0
0 1 0 0 1 1
1 0 0 1 0 1
1 1 1 1 1 1
Subtopic:  Logic gates |
 75%
From NCERT
AIPMT - 2007
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