The output \((X)\) of the logic circuit shown in the figure will be: 
  
1. \(X= \overline{A\cdot B}\)
2. \(X = A\cdot B\)
3. \(X= \overline{A+ B}\)
4. \(X=\overline{\overline{A}} \cdot \overline{\overline{B}}\)

Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is:
    
1. \(0.75~\text{A}\)
2. zero
3. \(0.25~\text{A}\)
4. \(0.5~\text{A}\)

Transfer characteristics [output voltage (${\mathrm{V}}_{\mathrm{o}}$) vs input voltage (${\mathrm{V}}_{\mathrm{i}}$)] for a base biased transistor in CE configurations are as shown in the figure. For using the transistor as a switch, it is used:

1. In region III

2. Both in the region (I) and (III)

3. In region II

4. In region I

The symbolic representation of four gates is shown as: 
   
Pick out which ones are for AND, NAND, and NOT gates, respectively.

A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω and an output impedance of 200 Ω. The power gain of the amplifier is:

1. 500

2. 1000

3. 1250

4. 50

To get an output Y = 1 from the circuit shown below, the input must be:

1. A=0 B=1 C=0

2. A=0 B=0 C=1

3. A=1 B=0 C=1

4. A=1 B=0 C=0

The circuit is equivalent to: 
     

1. AND gate
2. NAND gate
3. NOR gate
4. OR gate

In the following circuit, the output \(Y\) for all possible inputs \(A\) and \(B\) is expressed by the truth table: