Q. No.A current of \(3~\text{A}\) flows through the \(2~\Omega\) resistor shown in the circuit. The power dissipated in the \(5~\Omega\) resistor is:
1.
\(4~\text{W}\)
2.
\(2~\text{W}\)
3.
\(1~\text{W}\)
4.
\(5~\text{W}\)
| 1. | \(4~\text{W}\) | 2. | \(2~\text{W}\) |
| 3. | \(1~\text{W}\) | 4. | \(5~\text{W}\) |
1. 1.2 times, 1.1 times
2. 1.21 times, same
3. both remain the same
4. 1.1 times, 1.1 times
| 1. | \(6.3\) min | 2. | \(8.4\) min |
| 3. | \(12.6\) min | 4. | \(4.2\) min |
A cell can be balanced against 100 cm and 110 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is:
1. 1.0 Ω
2. 0.5 Ω
3. 2.0 Ω
4. zero
1. 1.5 V
2. 1.0 V
3. 0.5 V
4. 3.2 V
The total power dissipated in watts in the circuit shown below is:
| 1. | \(16\) W | 2. | \(40\) W |
| 3. | \(54\) W | 4. | \(4\) W |
Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
| 1. | \(2~\Omega\) | 2. | \(3~\Omega\) |
| 3. | \(6~\Omega\) | 4. | \(1~\Omega\) |
| 1. | flow from \(A\) to \(B\) |
| 2. | flow in the direction which will be decided by the value of \(V\) |
| 3. | be zero |
| 4. | flow from \(B\) to \(A\) |
Two cells having the same emf, are connected in series through an external resistance R. Cells have internal resistance r1 and r2 respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of R is:
1.
2.
3.
4.
The power dissipated across the \(8~\Omega\) resistor in the circuit shown here is \(2~\text{W}\). The power dissipated in watts across the \(3~\Omega\) resistor is:
| 1. | \(2.0\) | 2. | \(1.0\) |
| 3. | \(0.5\) | 4. | \(3.0\) |
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