Acetaldehyde reacts with                

1. Only electrophiles

2. Only nucleophiles

3. Only free radicals

4. Both electrophiles and nucleophiles

Which compounds will not reduce Fehling's solution?

1. Methanal                                 

2. Ethanal

3. Trichloroethanal                       

4. Benzaldehyde

Fehling's solution is:

1. Acidified copper sulphate solution

2. Ammoniacal cuprous chloride solution

3. Copper sulphate, Rochelle salt + NaOH

4. None of the above

Benzaldehyde and acetaldehyde can be distinguished by:

1. Iodoform test

2. 2:4 DNP test

3. ${\mathrm{NH}}_3$ reaction

4. Wolff-Kishner's reduction

The conversion of CH₃OH to CH₃COOH can be brought in by:

1. K₂Cr₂O₇/H⁺                           

2. CO + Rh

3. KMnO₄                                   

4. H₃PO₄

Polarisation of electrons in acrolein may be written as             

1. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\mathrm{CH}=\stackrel{\mathrm{\delta }-}{\mathrm{O}}$

2. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{}{\mathrm{O}}$

3. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{\delta +}{\mathrm{O}}$

4. $\stackrel{\mathrm{\delta }-}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}=\mathrm{O}$

Dry distillation of barium salt of Hexane-1,2-dicarboxylic acid gives:

1. 

2. 

3. 

4. 

Ethyl ester $\underset{\mathrm{Excess}}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$ P.

The product P will be

1.		2.
3.		4.

RCOOH $\to$RCH₂OH. This mode of reduction of an acid to alcohol can be affected only by:

1. Zn/HCl

2. Na-alcohol

3. aluminium isopropoxide and isopropyl alcohol

4. LiAlH₄

Compound (A) C₅H₁₀O forms a phenyl hydrazone and gives negative Tollen's and iodoform tests. Also, compound (A) on reduction gives n-pentane. Compound (A) is-