The current from the battery in circuit diagram shown is 

(1) 1 A

(2) 2 A

(3) 1.5 A

(4) 3 A

In the given circuit, the potential of the point E is 

(1) Zero

(2) –8 V

(3) –4/3 V

(4) 4/3 V

A battery of emf \(10\) V is connected to resistance as shown in the figure below. The potential difference \(V_{A} - V_{B}\)
between the points \(A\) and \(B\) is:

1. \(-2\) V

2. \(2\) V

3. \(5\) V

4. \(\frac{20}{11}~\text{V}\)

The equivalent resistance of the following infinite network of resistances is 

(1) Less than 4 Ω

(2) 4 Ω

(3) More than 4 Ω but less than 12 Ω

(4) 12 Ω

In the figure given below, the current passing through 6 Ω resistor is 

(1) 0.40 ampere

(2) 0.48 ampere

(3) 0.72 ampere

(4) 0.80 ampere

In the circuit shown, the point ‘B’ is earthed. The potential at the point ‘A’ is :

(1) 14 V

(2) 24 V

(3) 26 V

(4) 50 V

What is the current (i) in the circuit as shown in figure 

(1) 2 A

(2) 1.2 A

(3) 1 A

(4) 0.5 A

n equal resistors are first connected in series and then connected in parallel. What is the ratio of the maximum to the minimum resistance 

(1) n

(2) $\frac{1}{n^2}$

(3) n²

(4) $\frac{1}{n}$

What is the equivalent resistance between A and B in the figure below if R = 3 Ω 

(1) 9 Ω

(2) 12 Ω

(3) 15 Ω

(4) None of these

What is the equivalent resistance of the circuit​​​​​?

1. \(6~\Omega\)
2. \(7~\Omega\)
3. \(8~\Omega\)
4. \(9~\Omega\)