The latent heat of vaporisation of water is 2240 J/gm. If the work done in the process of expansion of 1 g is 168 J, then increase in internal energy is 

(1) 2408 J

(2) 2240 J

(3) 2072 J

(4) 1904 J

Subtopic:  First Law of Thermodynamics |
 82%
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A cylinder fitted with a piston contains 0.2 moles of air at temperature 27°C. The piston is pushed so slowly that the air within the cylinder remains in thermal equilibrium with the surroundings. Find the approximate work done by the system if the final volume is twice the initial volume 

(1) 543 J

(2) 345 J

(3) 453 J

(4) 600 J

Subtopic:  Work Done by a Gas |
 66%
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If a cylinder containing a gas at high pressure explodes, the gas undergoes -

(1) Reversible adiabatic change and fall of temperature

(2) Reversible adiabatic change and rise of temperature

(3) Irreversible adiabatic change and fall of temperature

(4) Irreversible adiabatic change and rise of temperature

Subtopic:  First Law of Thermodynamics |
 59%
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The work done in an adiabatic change in a gas depends only on

(1) Change is pressure

(2) Change is volume

(3) Change in temperature

(4) None of the above

Subtopic:  Work Done by a Gas |
 68%
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In adiabatic expansion 

(1) ΔU = 0

(2) ΔU = negative

(3) ΔU = positive

(4) ΔW = zero

Subtopic:  First Law of Thermodynamics |
 72%
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The pressure and density of a diatomic gas (γ=7/5) changes adiabatically from (P, d) to (P', d'). If d'd=32, then P'P should be: 

1. 1/128 2. 32
3. 128 4. None of the above
Subtopic:  Types of Processes |
 67%
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An ideal gas at 27°C is compressed adiabatically to 827 of its original volume. If γ=53, then the rise in temperature is

(1) 450 K

(2) 375 K

(3) 225 K

(4) 405 K

Subtopic:  Types of Processes |
 76%
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Two identical samples of a gas are allowed to expand, (i) isothermally and (ii) adiabatically. The work done will be:

1. more in the isothermal process.
2. more in the adiabatic process.
3. equal in both processes.
4. none of the above.

Subtopic:  Work Done by a Gas |
 68%
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Which is the correct statement ?

(1) For an isothermal change PV = constant

(2) In an isothermal process the change in internal energy must be equal to the work done

(3) For an adiabatic change P2P1=V2V1γ, where γ is the ratio of specific heats

(4) In an adiabatic process work done must be equal to the heat entering the system

Subtopic:  Types of Processes |
 81%
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The slopes of isothermal and adiabatic curves are related as:
1. Isothermal curve slope = adiabatic curve slope
2. Isothermal curve slope = \(\gamma \times\) adiabatic curve slope
3. Adiabatic curve slope = \(\gamma \times\) isothermal curve slope
4. Adiabatic curve slope = \(\frac{1}{2}\times\) isothermal curve slope
Subtopic:  Types of Processes |
 75%
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