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Q. No.If 0.02 moles of H2SO4 are present in 1 litre of solution from which 50% solution is taken out and again diluted up to 1 litre by adding water. Further, if 0.01 moles of H2SO4 are added, then the total millimoles of H2SO4 in the resulting solution will be:
1. 10
2. 5
3. 20
4. 15
1. 10
2. 5
3. 20
4. 15
Subtopic: Concentration Based Problem |
55%
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The percentages of C, H, and N in an organic compound are 40%, 13.3%, and 46.7% respectively.
The empirical formula of the compound is:
| 1. | C3H13N3 | 2. | CH2N |
| 3. | CH4N | 4. | CH6N |
Subtopic: Empirical & Molecular Formula |
74%
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AIPMT - 2002
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224 ml of a triatomic gas weighs 1g at 273 K and 1 atm. The mass of one atom of this gas is:
1. 8.30 × 10–23 g
2. 2.08 × 10–23 g
3. 5.53 × 10–23 g
4. 6.24 × 10–23 g
Subtopic: Moles, Atoms & Electrons |
53%
From NCERT
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Which of the following statements about the reaction given below is correct?
| 1. | Total mass of iron and oxygen in reactants = total mass of iron and oxygen in product therefore it follows the law of conservation of mass |
| 2. | Total mass of reactants = total mass of product, therefore, the law of multiple proportions is followed |
| 3. | The amount of Fe2O3 can be increased by taking any one of the reactants (iron or oxygen) in excess. |
| 4. | The amount of Fe2O3 produced will decrease if the amount of any one of the reactants (iron or oxygen) is taken in excess. |
Subtopic: Limiting Reagent |
74%
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Which one of the following samples of gases contains the most particles?
All gases are at 0 °C and 1 atm pressure when 1 mole of gas has a volume of 22.4 L.
[Relative atomic mass, Ar : H = 1, He = 4, C = 12, O = 16, Cl = 35.5]
1. 33.6 L of chlorine gas
2. 66.0 g of carbon dioxide gas
3. 22.4 L of hydrogen gas
4. 10.0 g of helium gas
All gases are at 0 °C and 1 atm pressure when 1 mole of gas has a volume of 22.4 L.
[Relative atomic mass, Ar : H = 1, He = 4, C = 12, O = 16, Cl = 35.5]
1. 33.6 L of chlorine gas
2. 66.0 g of carbon dioxide gas
3. 22.4 L of hydrogen gas
4. 10.0 g of helium gas
Subtopic: Moles, Atoms & Electrons |
51%
From NCERT
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The molarity of \(NaNO_3 \) solution (molecular weight of \(NaNO_3\) = 85) is 1M. The density of the solution is 1.25 gm/ml. The molality of the solution, approximately, will be:
1. 0.80
2. 0.86
3. 0.96
4. 1
1. 0.80
2. 0.86
3. 0.96
4. 1
Subtopic: Concentration Based Problem |
60%
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The number of moles of water present in a spherical water droplet of radius 1.0 cm are:
[Given: Density of water in the droplet = 1.0 g cm–3]
1. \( \dfrac{\pi}{18} \)
2. \( \dfrac{2\pi}{27} \)
3. \(24\pi\)
4. \( \dfrac{2\pi}{9} \)
[Given: Density of water in the droplet = 1.0 g cm–3]
1. \( \dfrac{\pi}{18} \)
2. \( \dfrac{2\pi}{27} \)
3. \(24\pi\)
4. \( \dfrac{2\pi}{9} \)
Subtopic: Introduction |
66%
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Two elements A & B form two different compounds A2B & AB3. If 0.15 mole of both compounds have equal weight then what is the ratio of the molar atomic mass of A & B?
1. 2 : 1
2. 6 : 4
3. 1 : 2
4. 4 : 6
1. 2 : 1
2. 6 : 4
3. 1 : 2
4. 4 : 6
Subtopic: Moles, Atoms & Electrons |
59%
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The number of molecules and moles in 2.8375 litres of \(O_2\) in STP is-
| 1. | \(1.505 \times 10^{23} \) and 0.250 | 2. | \(7.625 \times 10^{23} \) and 0.250 |
| 3. | \(7.625 \times 10^{22} \) and 0.126 | 4. | \(7.527 \times 10^{22} \) and 0.125 |
Subtopic: Moles, Atoms & Electrons |
58%
From NCERT
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Sulphuric acid reacts with sodium hydroxide as follows
When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-
1. 0.1 M, 7.10 g
2. 7.10 g, 0.025 M
3. 0.025 M, 3.55 g
4. 3.55 g, 0.25 M
Subtopic: Concentration Based Problem |
57%
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