Calculate the energy corresponding to light of wavelength 45 nm:
(Planck's constant h = 6.63 × 10^–34 Js:
speed of light c = 3 × 10⁸ ms^–1)
1. 6.67 x 10¹⁵ J
2. 6.67 x 10¹¹ J
3. 4.42 x 10^-15 J
4. 4.42 x 10^-18 J

If the energy value is E = 3.03 × 10^–19 Joules, (h = 6.6×10^–34 J x sec., C = 3×10⁸ m/sec), then the value of the corresponding wavelength is:

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at:

1. 1035 nm

2. 325 nm

3. 743 nm

4. 518 nm