Given lanthanoid ions ,the tendency to form the complexes is highest for:

1. Ce⁺³

2. Pm⁺²

3. Lu⁺³

4. Eu⁺²

When neutral or faintly alkaline $KMn{O}_4$ is treated with potassium iodide, iodide ion is converted into 'X'. 'X' is:

1. $I_2$

2. $I{O}_4^{-}$

3. $I{O}_3^{-}$

4. $I{O}^{-}$

A colored ion in aqueous solutions among the following is:

1. La³⁺ (Z=57)

2. Ti³⁺ (Z=22)

3. Lu³⁺ (Z=71)

4. Sc³⁺ (Z=21)

Four statements for Cr and Mn are given below:

The correct statements are 

1. (I), (III),(IV)

2. (I) , (II)

3. (I), (II) and (IV)

4. (I), (IV)

${\mathrm{Cr}}_2{\mathrm{O}}_7^{2-} + \mathrm{X} \stackrel{{\mathrm{H}}^{+}}{\to } {\mathrm{Cr}}^{3+} + {\mathrm{H}}_2\mathrm{O} +$ oxidised product of X
X in the above reaction can not be:
 

1. ${\mathrm{C}}_2{\mathrm{O}}_4^{2-}$

2. ${\mathrm{Fe}}^{2+}$

3. ${\mathrm{SO}}_4^{2-}$

4. ${\mathrm{S}}^{2-}$

Identify the incorrect statement.

Urea reacts with water to form A which will decompose to form B. B when passed through \(\left(Cu\right)^{2 +}\) (aq), deep blue colour solution C is formed. What is the formula of C from the following?

The manganate and permanganate ions are tetrahedral, due to: