Which one of the following compounds on treatment with LiAlH₄ will give a product that will give a positive iodoform test?

1. CH₃CH₂CHO                             

2. CH₃CH₂COOCH₃

3. CH₃CH₂OCH₂CH₃                      

4. CH₃COCH₃

In this reaction,

\(CH_{3}CHO \ + \ HCN \ \xrightarrow[]{} \ CH_{3}CH(OH)CN \ \xrightarrow[]{\textbf{H.OH}} \\ CH_{3}CH(OH)COOH\)

an asymmetric compound is generated. The acid obtained would be:        

1. 50% D + 50% L-isomer

2. 20% D + 80% L-isomer

3. D-isomer

4. L-isomer

Which of the following has most acidic hydrogen?

1. 3-hexanone                         

2. 2,4-hexanedione

3. 2,5-hexanedione                   

4. 2,3-hexanedione

Acetaldehyde reacts with                

1. Only electrophiles

2. Only nucleophiles

3. Only free radicals

4. Both electrophiles and nucleophiles

Which compounds will not reduce Fehling's solution?

1. Methanal                                 

2. Ethanal

3. Trichloroethanal                       

4. Benzaldehyde

Fehling's solution is:

1. Acidified copper sulphate solution

2. Ammoniacal cuprous chloride solution

3. Copper sulphate, Rochelle salt + NaOH

4. None of the above

Benzaldehyde and acetaldehyde can be distinguished by:

1. Iodoform test

2. 2:4 DNP test

3. ${\mathrm{NH}}_3$ reaction

4. Wolff-Kishner's reduction

The conversion of CH₃OH to CH₃COOH can be brought in by:

1. K₂Cr₂O₇/H⁺                           

2. CO + Rh

3. KMnO₄                                   

4. H₃PO₄

Polarisation of electrons in acrolein may be written as             

1. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\mathrm{CH}=\stackrel{\mathrm{\delta }-}{\mathrm{O}}$

2. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{}{\mathrm{O}}$

3. $\stackrel{\mathrm{\delta }+}{\mathrm{C}}{\mathrm{H}}_2=\stackrel{}{\mathrm{C}}\mathrm{H}-\mathrm{CH}=\stackrel{\delta +}{\mathrm{O}}$

4. $\stackrel{\mathrm{\delta }-}{\mathrm{C}}{\mathrm{H}}_2=\mathrm{CH}-\stackrel{\mathrm{\delta }+}{\mathrm{C}}\mathrm{H}=\mathrm{O}$

Dry distillation of barium salt of Hexane-1,2-dicarboxylic acid gives:

1. 

2. 

3. 

4.