Among the following atomic orbital overlaps, the non-bonding overlap is:
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A pair in which both species are not likely to exist is:
1. | \(H^+_2,He^{2-}_2\) | 2. | \(H^-_2,He^{2+}_2\) |
3. | \(H^{2+}_2,He_2\) | 4. | \(H^+_2,He^{2+}_2\) |
Amongst the one with the highest boiling point is:
1. H2O because of H-bonding.
2. H2Te because of higher molecular weight.
3. H2S because of H-bonding.
4. H2Se because of lower molecular weight.
The correct order of electronegativity of hybrid orbitals of carbon is:
1. sp > sp2 < sp3
2. sp > sp2 > sp3
3. sp < sp2 > sp3
4. sp < sp2 < sp3
What is the correct order of C−O bond lengths among \(\mathrm{CO},\mathrm{CO}_3^{2-},\) and \(\mathrm{CO_2}\) ?
1. \(\mathrm{CO}_2<\mathrm{CO}_3^{2-}<\mathrm{CO} \)
2. \(\mathrm{CO}<\mathrm{CO}_3^{2-}<\mathrm{CO}_2 \)
3. \(\mathrm{CO}_3^{2-}<\mathrm{CO}_2<\mathrm{CO} \)
4. \(\mathrm{CO}<\mathrm{CO}_2<\mathrm{CO}_3^{2-}\)
Mg2C3 reacts with water forming propyne . The number of sigma and pie bonds in \(C_{3}^{4-}\)is-
1. Two sigma and two pi bonds.
2. Three sigma and one pi bonds.
3. Two sigma and one pi bonds.
4. Two sigma and three pi bonds.
Compound in which central atom assumes sp3d hybridisation is
1. SO3
2. PCl5
3. SO2
4. PCl3
Which of the following molecules have unequal bonds?
1.
2.
3.
4.
Which of the following molecules contain bond angles of 180° in their gaseous states?
(Atomic numbers: H = 1; Be = 4; C = 6; Cl = 17)
A. BeCl2
B. C2H2
C. CCl4
1. | A and C only | 2. | A and B only |
3. | A only | 4. | B and C only |