Pink colour of acidified \(KMnO_4\) is decolourised but there is no evolution of any gas. This may happen with the compound containing the following acid radical (s):
1.
\(SO^{2-}_3\)
2.
\(NO^{-}_2\)
3.
\(S^{2-}\)
4.
All of the above
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Salt (A), when heated, releases a colorless neutral gas that supports combustion. Based on the diagram provided, it can be concluded that compound (A) contains the following acid radical:
1.
\(\mathrm{NO}_2^{-} \)
2.
\(\mathrm{NO}_3^{-} \)
3.
\(\mathrm{Br}^ - \)
4.
\(\mathrm{SO}_3{ }^{2-}\)
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Salt (A) on heating gives a colourless neutral gas that supports combustion. It can be concluded, based on the diagram given above that the correct statement(s) among the following is/are:
1. Salt (A) gives a yellow precipitate with chloroplatinic acid as well as with sodium cobaltinitrite.
2. The brown ring is formed due to the formation of nitroso ferrous sulphate \([\mathrm{Fe}(\mathrm{NO})]^{2+} \mathrm{SO}_4^{-}\)
3. Salt ‘C’ reacts with silver nitrate solution to form a white precipitate.
4. (A) and (B) both.
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A substance on treatment with dil. \(H_2SO_4\) liberates a colourless gas that produces
(i) turbidity with baryta water
(ii) turns acidified dichromate solution green
The reaction indicates the presence of:
1. \(CO^{2-}_3\)
2. \(S^{2-}\)
3. \(SO^{2-}_3\)
4. \(NO^{-}_2\)
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The brown ring test for NO3- is enabled due to the formation of the complex ion with the formula:
1. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \)
2. \(\mathrm{Fe}\left[\mathrm{NO}(\mathrm{CN})_5\right]^{2-} \)
3. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right]^{2+} \)
4. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)(\mathrm{NO})_5\right]^{2+} \)
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